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Can anyone please explain how the probability of getting green marble in the second condition is 3/5?
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Balakumaran19
Can anyone please explain how the probability of getting green marble in the second condition is 3/5?

The total number of marbles in Box B is 5 (2 Red and 3 Green). Therefore the probability of green marble is Green marble/Total marbles in Box B which is 3/5. Hope this helps!
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RedGreenTot
A358
B235

Prob. A = 1 or 6 (out of 6) = \(\frac{2}{6}\) = \(\frac{1}{3}\)
Prob. B = 2 or 3 or 4 or 5 (out of 6) = \(\frac{4}{6}\) =\(\frac{2}{3}\)

->

\(\frac{1}{3}*\frac{5}{8}+\frac{2}{3}*\frac{3}{5}=\frac{2}{5}*\frac{5}{24}=\frac{48+25}{120}=\frac{73}{120}\)
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2/6 x 5/8 + 4/6 x 3/5 =73/120
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