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iwo
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there are two triangles whose three vertices have same Updated on: 02 Nov 2007, 19:08
Originally posted by iwo on 02 Nov 2007, 17:49.
Last edited by iwo on 02 Nov 2007, 19:08, edited 1 time in total.
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there are two triangles whose three vertices have same angles (x, y, z). If area of one triangle is twice the area of the other triangle, and the base of the smaller triangle is s, and base of the larger triangle is S, then what is S, in terms of s?

√2/2 s
√3/2 s
√2 s
√3 s
2 s



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beckee529
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there are two triangles whose three vertices have same 02 Nov 2007, 18:12
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iwo
there are two triangles whose vertices have same angles. If area of one triangle is twice the area of the other triangle, and the base of the smaller triangle is s, and base of the larger triangle is S, then what is S, in terms of s?

√2/2 s
√3/2 s
√2 s
√3 s
2 s
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vertices have same angles <-- that tells us we are dealing with equilateral triangles with 60 degrees for each angle, so the height will be split with the 30-60-90 degree and will be 1/2*base* √3

i get A (although not 100% sure) please confirm

so lets start with the larger triangle
area = 1/2bh, stem tells us base is big S
area = 1/2 S * (√3)/2 S

smaller triangle
area = 1/2bh, base is little s
area = 1/2 s * (√3)/2 s

since area for larger triangle is twice that of the smaller
than S * (√3)/2S = 1/2 s * (√3)/2s

solving for S (multiply inverse 2/√3 on both sides to clear LHS)

S^2 = √3/4 s^2 * 2/√3
S^2 = s^2 * 2/4
and take the sqrt on both sides:
S = s * √(1/2)
S = s * √2/2
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iwo
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there are two triangles whose three vertices have same 02 Nov 2007, 19:06
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nope thats not the OA

both triangles have same angles x-y-z, no degrees are given, sorry i forgot to mention that
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beckee529
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there are two triangles whose three vertices have same 02 Nov 2007, 19:21
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iwo
nope thats not the OA

both triangles have same angles x-y-z, no degrees are given, sorry i forgot to mention that
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duh!!! sorry i know where i screwed up (hope not on test day)

continuation...

since area for larger triangle is twice that of the smaller
than S * √3/4S = 2* (s * √3/4s)

solving for S (multiply inverse 4/√3 on both sides to clear LHS)

S^2 = √3/2 s^2 * 4/√3
S^2 = s^2 * 4/2
and take the sqrt on both sides:
S = s * √2
so the third choice.. . is that correct?
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there are two triangles whose three vertices have same 02 Nov 2007, 23:53
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iwo
there are two triangles whose three vertices have same angles (x, y, z). If area of one triangle is twice the area of the other triangle, and the base of the smaller triangle is s, and base of the larger triangle is S, then what is S, in terms of s?

√2/2 s
√3/2 s
√2 s
√3 s
2 s
Show more


Getting C.

The ratio of the area of similar triangles is the square of the ratio of similar sides.

Since all three angles are equal the 2 triangles are similar.

Ratio of ar. of small triangle : ratio of ar. of big triangle = 1:2
Therefore, ratio of sides of small triangle : ratio of sides of big triangle = 1 : sqrt(2)

If s = 1 then S = sqrt(2)s



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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