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cloaked_vessel
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There is a set of 2000 numbers, beginning at 7, with each 06 Mar 2005, 18:30
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There is a set of 2000 numbers, beginning at 7, with each subsequent term increasing by 3. What is the average of the set? What is the median of the set?



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There is a set of 2000 numbers, beginning at 7, with each 06 Mar 2005, 18:44
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I try a fast answer , I think median and average are the same number.

median is the 1000th term, and the set is built like this : 7+3*n
so 1000th term is 7+3*1000 = 3007
I suppose it is also the average.
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There is a set of 2000 numbers, beginning at 7, with each 06 Mar 2005, 18:49
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I don't have OA on this. I wanted to see what other people say to this question.
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There is a set of 2000 numbers, beginning at 7, with each 06 Mar 2005, 18:51
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If we're talking about equally space values (in this case we refer to a space of 3), average should be : (min value + max)/2
min : 7
max : 7+3*2000 = 6007
average = (7 + 6007)/2 = 6014/2 = 3007 (which confirms my 1st post)
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MA
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There is a set of 2000 numbers, beginning at 7, with each 06 Mar 2005, 19:07
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cloaked_vessel
There is a set of 2000 numbers, beginning at 7, with each subsequent term increasing by 3. What is the average of the set? What is the median of the set?
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first term = 7
last term = 7+1999x3=7+5997=6004
sum = n(L+F)/2 = 2000(7+6004)/2=1000*6011
avarage = sum/n=(1000x6011)/2000=3005.5
median is also the same.
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There is a set of 2000 numbers, beginning at 7, with each 06 Mar 2005, 19:17
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MA corrected my previous post :oops:

last term is 6004
average is (7+6004)/2 = 3005.5
median is same

good job MA
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There is a set of 2000 numbers, beginning at 7, with each 06 Mar 2005, 20:34
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Mean is 3005.5
Median is 3005.5

Tn= a +(n-1)d
last term = 7 +(2000-1)3=6004
Average=first term+last term= (7+ 6004)/2=6011/2= 3005.5

Median= (value of 1000 th term +1001th term)/2= (3004+3007)/2=3005.5
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There is a set of 2000 numbers, beginning at 7, with each 06 Mar 2005, 23:02
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agree, Besides

average and median can be integer as the number within the set is even.
Because it is even and regular set, we just need to figure out the first and last number of the set and divide by two.
for the same reason we know that median = average
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There is a set of 2000 numbers, beginning at 7, with each 07 Mar 2005, 10:29
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3005.5
this was a tricky one ...i too just took 2000 instead of 1999
nice one
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There is a set of 2000 numbers, beginning at 7, with each 07 Mar 2005, 10:44
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T1=7
T2000= 7+(1999*3)=(6004

t1+t2000)/2 =3005.5

both mean n median is 3005.5



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