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tzolkin
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Curly05
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stolyar
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coin is flipped 5 times. What is the probability that there are at least 3 heads ?

Stolyar, do you realize 10C3 works out to 120, I'm lost here.

:madd
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tzolkin
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Can you not use the Binomial Equation ?

P = 5C3*(1/2)^3*(1/2)^2
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Although I've never heard of it until now, Tzolkin, if you state we should spend more time doing "ETS" style, then don't worry about this question. :wink: Spend more time with algebra and geometry, why are we all obsessed about probability :roll:
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kheriapiyush@indiatimes.c
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I agree that Binomial method can be applied to this problem

p1 = probability that it is Heads = 1/2
p2 = probablity that it is not Heads = 1/2

P = 5C3 (p1)^3 (p2)^2 = 0.3215

some one please confirm the answer.
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tzolkin
Can you not use the Binomial Equation ?

P = 5C3*(1/2)^3*(1/2)^2


Tzolkin

The case you state here is only for 3 heads. The question asks for ATLEAST three heads = 3 or 4 or 5 heads.

Therefore, using bionomial equation

P(atleast 3 heads) = 5C3+5C4+5C5 / (1/2)^5 = 16/32 = 1/2



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