Three containers A, B and C are having mixtures of milk and water in

Looking at the various ratios, A:B:C sizes are in the ratio of 5:4:5 and each have a ratio of milk to water respectively of 1:5, 3:5 and 5:7. Which means A's total mixture is a value which is divisible by 6, B's is divisible by 8 and C's is divisible by 12.

Looking at A and C alone, 120 liters is a good size to work with. Let A be 120 liters big, let B also be 120 liters big, which then means that C will be 96 liters big. (the ratio of A:B:C is multiplied right through by 24 to set a size to each container)

As the sizes have been set, now one can add actual liter values to the respective milk to water ratios:

Container A: 120 liters in the ratio 1:5 becomes 20l of milk and 100l of water.

Container B: 96 liters in the ratio 3:5 becomes 36l of milk and 60l of water.

Container C: 120 liters in the ratio 5:7 becomes 50l of milk and 70l of water.

Summing the milk and water: Milk: \(20+36+50 = 106\) Water:\(100+60+70 = 230\)

Ratio of milk to water = 106:230 which when simplified is 53:115

Answer A