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# Three friends rented a car for a week and divided the cost equally. If

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Manager
Joined: 13 Sep 2016
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Three friends rented a car for a week and divided the cost equally. If  [#permalink]

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10 May 2018, 02:54
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15% (low)

Question Stats:

89% (01:15) correct 11% (01:19) wrong based on 43 sessions

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Three friends rented a car for a week and divided the cost equally. If a fourth friend had joined them and the cost had been divided equally among the 4 friends, then the cost to each of the original 3 friends would have been reduced by $15? What was the total cost of renting the car? a)$60
b) $100 c)$140
d) $160 e)$180
Manager
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Re: Three friends rented a car for a week and divided the cost equally. If  [#permalink]

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10 May 2018, 03:04
Let the initial cost for each of the three friends be x units.
Total cost =3x units
Now, a new guy came in then the cost per friend =3x/4 units
reduction in cost =x-3x/4=x/4 ; And x/4 =15 =>x=60
total cost =3*60=180 =>E
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Re: Three friends rented a car for a week and divided the cost equally. If  [#permalink]

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10 May 2018, 03:15
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alanforde800Maximus wrote:
Three friends rented a car for a week and divided the cost equally. If a fourth friend had joined them and the cost had been divided equally among the 4 friends, then the cost to each of the original 3 friends would have been reduced by $15? What was the total cost of renting the car? a)$60
b) $100 c)$140
d) $160 e)$180

OA: E

Total cost of trip : x
as per question stem
$$\frac{x}{3}-\frac{x}{4}=15$$
$$\frac{x}{12}=15$$
$$x=12*15=180$$
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Re: Three friends rented a car for a week and divided the cost equally. If  [#permalink]

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10 May 2018, 06:33
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alanforde800Maximus wrote:
Three friends rented a car for a week and divided the cost equally. If a fourth friend had joined them and the cost had been divided equally among the 4 friends, then the cost to each of the original 3 friends would have been reduced by $15? What was the total cost of renting the car? a)$60
b) $100 c)$140
d) $160 e)$180

Let's start with a word equation: (cost per person with 4 friends) = (cost per person with 3 friends) - $15 Let T = the total cost of renting the car So, cost per person with 4 friends = T/4 And cost per person with 3 friends = T/3 We can now take our word equation and fill in the missing parts to get: T/4 = T/3 - 15 To eliminate the fractions, multiply both sides by 12 to get: (12T/4) = 12(T/3 - 15) Expand: 3T = 4T - 180 Solve: T = 180 Answer: E Cheers, Brent _________________ Brent Hanneson – GMATPrepNow.com Sign up for our free Question of the Day emails Intern Joined: 03 Dec 2017 Posts: 10 Re: Three friends rented a car for a week and divided the cost equally. If [#permalink] ### Show Tags 10 May 2018, 07:52 alanforde800Maximus wrote: Three friends rented a car for a week and divided the cost equally. If a fourth friend had joined them and the cost had been divided equally among the 4 friends, then the cost to each of the original 3 friends would have been reduced by$15? What was the total cost of renting the car?

a) $60 b)$100
c) $140 d)$160
e) $180 2step question cost for 4th firend --> 15*3 -- 45 total cost 45 * 4 -- 180 Target Test Prep Representative Status: Founder & CEO Affiliations: Target Test Prep Joined: 14 Oct 2015 Posts: 3886 Location: United States (CA) Re: Three friends rented a car for a week and divided the cost equally. If [#permalink] ### Show Tags 13 May 2018, 17:57 alanforde800Maximus wrote: Three friends rented a car for a week and divided the cost equally. If a fourth friend had joined them and the cost had been divided equally among the 4 friends, then the cost to each of the original 3 friends would have been reduced by$15? What was the total cost of renting the car?

a) $60 b)$100
c) $140 d)$160
e) \$180

We can let the cost of the rental = n and create the equation:

n/3 = n/4 + 15

Multiplying by 12, we have:

4n = 3n + 180

n = 180

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Re: Three friends rented a car for a week and divided the cost equally. If &nbs [#permalink] 13 May 2018, 17:57
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