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Three friends rented a car for a week and divided the cost equally. If

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Three friends rented a car for a week and divided the cost equally. If  [#permalink]

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New post 10 May 2018, 01:54
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Question Stats:

87% (01:21) correct 13% (01:32) wrong based on 54 sessions

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Three friends rented a car for a week and divided the cost equally. If a fourth friend had joined them and the cost had been divided equally among the 4 friends, then the cost to each of the original 3 friends would have been reduced by $15? What was the total cost of renting the car?

a) $60
b) $100
c) $140
d) $160
e) $180
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Re: Three friends rented a car for a week and divided the cost equally. If  [#permalink]

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New post 10 May 2018, 02:04
Let the initial cost for each of the three friends be x units.
Total cost =3x units
Now, a new guy came in then the cost per friend =3x/4 units
reduction in cost =x-3x/4=x/4 ; And x/4 =15 =>x=60
total cost =3*60=180 =>E
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Re: Three friends rented a car for a week and divided the cost equally. If  [#permalink]

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New post 10 May 2018, 02:15
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alanforde800Maximus wrote:
Three friends rented a car for a week and divided the cost equally. If a fourth friend had joined them and the cost had been divided equally among the 4 friends, then the cost to each of the original 3 friends would have been reduced by $15? What was the total cost of renting the car?

a) $60
b) $100
c) $140
d) $160
e) $180


OA: E

Total cost of trip : x
as per question stem
\(\frac{x}{3}-\frac{x}{4}=15\)
\(\frac{x}{12}=15\)
\(x=12*15=180\)
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Re: Three friends rented a car for a week and divided the cost equally. If  [#permalink]

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New post 10 May 2018, 05:33
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alanforde800Maximus wrote:
Three friends rented a car for a week and divided the cost equally. If a fourth friend had joined them and the cost had been divided equally among the 4 friends, then the cost to each of the original 3 friends would have been reduced by $15? What was the total cost of renting the car?

a) $60
b) $100
c) $140
d) $160
e) $180



Let's start with a word equation: (cost per person with 4 friends) = (cost per person with 3 friends) - $15

Let T = the total cost of renting the car

So, cost per person with 4 friends = T/4
And cost per person with 3 friends = T/3

We can now take our word equation and fill in the missing parts to get: T/4 = T/3 - 15
To eliminate the fractions, multiply both sides by 12 to get: (12T/4) = 12(T/3 - 15)
Expand: 3T = 4T - 180
Solve: T = 180

Answer: E

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Brent
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Re: Three friends rented a car for a week and divided the cost equally. If  [#permalink]

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New post 10 May 2018, 06:52
alanforde800Maximus wrote:
Three friends rented a car for a week and divided the cost equally. If a fourth friend had joined them and the cost had been divided equally among the 4 friends, then the cost to each of the original 3 friends would have been reduced by $15? What was the total cost of renting the car?

a) $60
b) $100
c) $140
d) $160
e) $180


2step question
cost for 4th firend --> 15*3 -- 45
total cost 45 * 4 -- 180
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Re: Three friends rented a car for a week and divided the cost equally. If  [#permalink]

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New post 13 May 2018, 16:57
alanforde800Maximus wrote:
Three friends rented a car for a week and divided the cost equally. If a fourth friend had joined them and the cost had been divided equally among the 4 friends, then the cost to each of the original 3 friends would have been reduced by $15? What was the total cost of renting the car?

a) $60
b) $100
c) $140
d) $160
e) $180


We can let the cost of the rental = n and create the equation:

n/3 = n/4 + 15

Multiplying by 12, we have:

4n = 3n + 180

n = 180

Answer: E
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Re: Three friends rented a car for a week and divided the cost equally. If &nbs [#permalink] 13 May 2018, 16:57
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