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28 Feb 2026, 15:57
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C
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Difficulty:
55%
(hard)
Question Stats:
67% (02:52) correct
33%
(03:29)
wrong
based on 55
sessions
History
Date
Time
Result
Not Attempted Yet
Three machines working independently at their respective constant rates can peel 600 eggs in 2 hours, 3 hours, and 6 hours, respectively. On Day 1, each machine worked for the same number of hours until all 600 eggs were peeled. On Day 2, each machine peeled the same number of eggs until all 600 eggs were peeled. By approximately what percent did the total number of hours worked by the three machines combined on Day 2 exceed the total number of hours worked by the three machines combined on Day 1?
A) 11%
B) 17%
C) 22%
D) 25%
E) 33%
A) 11%
B) 17%
C) 22%
D) 25%
E) 33%
04 Mar 2026, 06:58
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kevincan
Day \(1\): "Each machine worked for the same number of hours until all 600 eggs were peeled."
This is only possible if each machine worked individually for \(1\) hr.
First machine in \(1\) hour \(= 300\)
Second machine in \(1\) hour \(= 200\)
Third machine in \(1\) hour \(= 100\)
Total time: \( 1+1+1 = 3\) hrs
Day \(2 \): "Each machine peeled the same number of eggs until all 600 eggs were peeled."
So each peeled \(200\) eggs.
Machine \(1\) to peel \(200\) eggs will take \(\frac{2}{600}*200 = \frac{2}{3}\) hrs
Machine \(2\) to peel \(200\) eggs will take \(\frac{3}{600}*200 = 1 \) hrs
Machine \(3\) to peel \(200\) eggs will take \(\frac{6}{600}*200 = 2 \) hrs
Total time: \(= \frac{2}{3} +1 +2 = \frac{11}{3}\)
(Day \(2\) time) \(/\) (Day \(1\) time ) \(= \frac{11}{9}=1.222 \) or \( 122.2 \%\)
Hence extra time taken by day \(2 \approx 22 \%\)
Ans C
Hope it helped.
