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Three musical tones have frequencies x, y, and z, respectively. If x,

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New post 09 Nov 2015, 00:22
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Three musical tones have frequencies x, y, and z, respectively. If x, y, and z are positive, x/y = y/z, and 2x = z, what is y in terms of x ?

(A) 2

(B) \(\sqrt{2}x\)

(C) \(\frac{x}{\sqrt{2}}\)

(D) x/2

(E) \(\frac{\sqrt{2}}{3}x\)
[Reveal] Spoiler: OA

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Re: Three musical tones have frequencies x, y, and z, respectively. If x, [#permalink]

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New post 09 Nov 2015, 00:58
Bunuel wrote:
Three musical tones have frequencies x, y, and z, respectively. If x, y, and z are positive, x/y = y/z, and 2x = z, what is y in terms of x ?

(A) 2

(B) \(\sqrt{2}x\)

(C) \(\frac{x}{\sqrt{2}}\)

(D) x/2

(E) \(\frac{\sqrt{2}}{3}x\)


Y^2= XZ, so substitute 2X instead of Z so it becomes 2X^2 therefore Y^2=2X^2, Y= Root of 2 and X, There fore my choice goes for B.

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Re: Three musical tones have frequencies x, y, and z, respectively. If x, [#permalink]

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New post 09 Nov 2015, 01:43
x/y = y/z ---1
=>y^2 = xz

Now substituting 2x=z , we have
y^2=x*2x= 2*x^2
=>y = x* 2^(1/2)
Answer B
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Re: Three musical tones have frequencies x, y, and z, respectively. If x, [#permalink]

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New post 21 Oct 2017, 09:26
\(\frac{x}{y}\)=\(\frac{y}{z}\) => \(y^2=xz\) -------------(1)
2x=z
Putting the value of z in equation (1)
\(y^2=2x^2\)
y=\(\sqrt{2}x\) or \(-\sqrt{2}x\)
Since x,y,z are positive,
y=\(\sqrt{2}x\)

Answer B.

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Re: Three musical tones have frequencies x, y, and z, respectively. If x,   [#permalink] 21 Oct 2017, 09:26
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