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09 Mar 2026, 19:00
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
76% (02:08) correct
24%
(02:44)
wrong
based on 100
sessions
History
Date
Time
Result
Not Attempted Yet
Three retailers A, B, and C bought the same item for sale at the same cost price. Retailer A decided to have a 50% mark-up and offered 40% discount on the marked price. Retailer B had a 100% mark-up and offered two successive discounts of 30% and 30% on the marked price. Retailer C marked up by 20% but, owing to lack of demand, had to eventually sell on 20% discount on the marked price. The selling price for the retailers was in what order?
A. B > C > A
B. B > A > C
C. C > A > B
D. C > B > A
E. A > B > C
A. B > C > A
B. B > A > C
C. C > A > B
D. C > B > A
E. A > B > C
09 Mar 2026, 22:44
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say selling price = 100x
for A
MP = 100x * (3/2)
MP = 150x
SP = 150x * (3/5)
SP = 90x
for B
MP = 100x * 2
MP = 200x
first 30% discount SP = 200x * (0.7)
(SP)1 = 140x
second 30% discount on 140x
(SP)2 = 140x * (0.7)
(SP)2 = 98x
for C
MP = 100x * (6/5)
MP = 120x
SP = 120x * (4/5)
SP = 24x * 4
SP = 96x
SP in order
A= 90x
B=98x
C = 96x
B>C>A
option A
for A
MP = 100x * (3/2)
MP = 150x
SP = 150x * (3/5)
SP = 90x
for B
MP = 100x * 2
MP = 200x
first 30% discount SP = 200x * (0.7)
(SP)1 = 140x
second 30% discount on 140x
(SP)2 = 140x * (0.7)
(SP)2 = 98x
for C
MP = 100x * (6/5)
MP = 120x
SP = 120x * (4/5)
SP = 24x * 4
SP = 96x
SP in order
A= 90x
B=98x
C = 96x
B>C>A
option A
ExpertsGlobal5
09 Mar 2026, 23:19
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Just work with percentages:
A=1.5x(0.6) = 0.9x
B=2x(0.49) = 0.98x [Successive discount formula once applied 30+30-30*30/100 = 51% discount]
C=1.2x(0.8) = 0.96x
Hence B>C>A
Answer: Option A
A=1.5x(0.6) = 0.9x
B=2x(0.49) = 0.98x [Successive discount formula once applied 30+30-30*30/100 = 51% discount]
C=1.2x(0.8) = 0.96x
Hence B>C>A
Answer: Option A
ExpertsGlobal5
10 Mar 2026, 00:36
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Classic markup-and-discount question — the kind that trips people up when there are successive discounts involved. Let's assign a cost price and work through each retailer.
Key concept being tested: Successive percentage changes (Percent and Interest Problems) — specifically, how successive discounts compound.
Let cost price = 100.
Step 1 — Retailer A: 50% markup → MP = 150. Then 40% discount on MP.
Selling price A = 150 × 0.60 = 90
Step 2 — Retailer B: 100% markup → MP = 200. Two successive 30% discounts.
After first discount: 200 × 0.70 = 140
After second discount: 140 × 0.70 = 98
Step 3 — Retailer C: 20% markup → MP = 120. 20% discount on MP.
Selling price C = 120 × 0.80 = 96
Step 4 — Order: B (98) > C (96) > A (90) → Answer: A (B > C > A)
Common trap: Students calculate B's double discount as a single 60% discount (thinking 30% + 30% = 60%), giving them 200 × 0.40 = 80. That's wrong — successive discounts are multiplicative, not additive. Two 30% discounts = 1 − (0.70 × 0.70) = 51% total discount, not 60%. This mistake flips B from the highest selling price to the lowest, completely reversing the order.
Also watch out for Retailer C — a 20% markup followed by a 20% discount does NOT get you back to cost price. You end up at 96, not 100. Equal markup and discount percentages are never a wash.
Answer: A (B > C > A)
Takeaway: Whenever you see successive discounts, always multiply the multipliers (0.70 × 0.70), never add the percentages — and remember that symmetrical markup and discount percentages will always result in a net loss, not a breakeven.
Key concept being tested: Successive percentage changes (Percent and Interest Problems) — specifically, how successive discounts compound.
Let cost price = 100.
Step 1 — Retailer A: 50% markup → MP = 150. Then 40% discount on MP.
Selling price A = 150 × 0.60 = 90
Step 2 — Retailer B: 100% markup → MP = 200. Two successive 30% discounts.
After first discount: 200 × 0.70 = 140
After second discount: 140 × 0.70 = 98
Step 3 — Retailer C: 20% markup → MP = 120. 20% discount on MP.
Selling price C = 120 × 0.80 = 96
Step 4 — Order: B (98) > C (96) > A (90) → Answer: A (B > C > A)
Common trap: Students calculate B's double discount as a single 60% discount (thinking 30% + 30% = 60%), giving them 200 × 0.40 = 80. That's wrong — successive discounts are multiplicative, not additive. Two 30% discounts = 1 − (0.70 × 0.70) = 51% total discount, not 60%. This mistake flips B from the highest selling price to the lowest, completely reversing the order.
Also watch out for Retailer C — a 20% markup followed by a 20% discount does NOT get you back to cost price. You end up at 96, not 100. Equal markup and discount percentages are never a wash.
Answer: A (B > C > A)
Takeaway: Whenever you see successive discounts, always multiply the multipliers (0.70 × 0.70), never add the percentages — and remember that symmetrical markup and discount percentages will always result in a net loss, not a breakeven.
