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24 Jun 2009, 03:09
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If a+b can perform a task in 12 days and b+c does the same in 20 days. How long will a+b+c take to complete the same task? Also deduce the indivisual performance.
Kindly show me the procedure to solve the same.
Kindly show me the procedure to solve the same.
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24 Jun 2009, 04:44
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I tried a different approach of picking numbers:
Let's say A and B take 24 hours each to complete I unit of tasks
1/24 + (1/24) = 1/12
Hence for B and C:
1/24 + (1/C)=1/20
Therefor C will take 120 hours to finish 1 unit of job
There A,B and C will take:
1/12 + 1/120 = 11/120
Hence total hours : 120/11
Is this approach correct?!
Let's say A and B take 24 hours each to complete I unit of tasks
1/24 + (1/24) = 1/12
Hence for B and C:
1/24 + (1/C)=1/20
Therefor C will take 120 hours to finish 1 unit of job
There A,B and C will take:
1/12 + 1/120 = 11/120
Hence total hours : 120/11
Is this approach correct?!
24 Jun 2009, 08:48
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I dont think it works? if i plug in 1/18 for A, 1/36 for B i get 45 for C and diff. answer....
