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Praetorian
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1. Time yourself
2. Work this problem on paper as fast as you can ( doing this under 2 mins is our goal)
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Two events A & B are such that P(A) = 0.83, P(B) = 0.25. If C is a set of possible values of probability that A & B both occur, Find the range of C?



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eyal
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Time yourself 2. Work this problem on paper as fast as you 08 Mar 2004, 03:57
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Am I missing something or is the answer X*Y = 0.2075 (30sec.)?
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kpadma
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P(C) = 0.2075
(Time less than a minute)
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Makky07
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That's a bad question. I don't see how there could be a range. There's only one possible answer and that is 0.207 which is not a range.
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If these two events are mutually exclusive then P(A&B) = 0
if these are independent events and not mutually exclusive
P(A&B) = P(A) & P(B) = 0.2075

If they are dependent events
P(A or B) = P(A) + P(B) - P(A&B)
Max of P(A OR B) = 1
P(A&B) = 0.83+0.25 - 1 = 0.08

Range is 0.08 to 0.2075
or the range is
0 to 0.2075
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ndidi204
That's a bad question. I don't see how there could be a range. There's only one possible answer and that is 0.207 which is not a range.


nope, i hope to prove that none of you is right.

Range = Maximum - Minimum
1. what is the Maximum possible value of C?
2. what is the Minimum possible value of C?
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Hi Praetorian,

Would you mind explaining the solution. Already enough people have pounded on this.

Anand.
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anandnk
Hi Praetorian,

Would you mind explaining the solution. Already enough people have pounded on this.

Anand.


Sure.

1. The events A and B cannot be mutually exclusive.
P(A) + P(B) > 1
so, the minimum value of C cannot be 0.
the minimum C is 0.83 + 0.25 - 1 = 0.08

2. About the maximum, that will occur when B is a subset of A.
that is C = 0.25


you answer then is Range = 0.25 -0.08 =0.17 :)

questions?
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Hmm,

I was atleast half right. Never thought of this scenario where B could be part of A.

Thanks,
Anand.
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anandnk
Hmm,

I was atleast half right. Never thought of this scenario where B could be part of A.

Thanks,
Anand.


I will give y'all answer choices next time.



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