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19 Apr 2010, 11:28
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remainder is included in gmat syllabus , i have not seen in OG any question to find the remainder of the composite number when it is divided by some number.
here is one example and the way to find the remainder
1. what is remainder when \(1421*1423*1425\) is divided by 12
classical way to solve this is to multiply all the numbers and then do the division operation to get remainder.
however, we can get remainder following way:
divide each number with given number separately go get the reminder of each number then multiply, do the operation as many times till resultant number is no more divisible by given number... it's little bit abstract:
let's try with above example : to get the remainder of \(1421*1423*1425\) when divided by 12 can be given as:
\(\frac{1421*1423*1425 }{12} ----R---------> \frac{5*7*9}{12} = \frac{35*9}{12}\\
---------R---------> \frac{11*9 }{12}\) --------R-------> gives us reminder of 3.
so the required remainder is 3. some more numbers..hope this will be useful tips thanks..
here is one example and the way to find the remainder
1. what is remainder when \(1421*1423*1425\) is divided by 12
classical way to solve this is to multiply all the numbers and then do the division operation to get remainder.
however, we can get remainder following way:
divide each number with given number separately go get the reminder of each number then multiply, do the operation as many times till resultant number is no more divisible by given number... it's little bit abstract:
let's try with above example : to get the remainder of \(1421*1423*1425\) when divided by 12 can be given as:
\(\frac{1421*1423*1425 }{12} ----R---------> \frac{5*7*9}{12} = \frac{35*9}{12}\\
---------R---------> \frac{11*9 }{12}\) --------R-------> gives us reminder of 3.
so the required remainder is 3. some more numbers..hope this will be useful tips thanks..
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19 Apr 2010, 14:01
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I love the internet. It's the only place where we can be so diverse that one person's short-cut is more confusing to me than the original problem. 
Thanks for the post, I'll come back later and re-read it to see why I find that harder.
Thanks for the post, I'll come back later and re-read it to see why I find that harder.
19 Apr 2010, 21:46
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joeleitz
nice quote .. actually you are correct, it is quite possible that one person's short cut is difficult to comprehend to other.. but given amount of typing it's difficult to explain step by step how to reach the short cut i mentioned ..try out it, and if you able to implement in your way i will be happy
thanks 
