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let me know if this makes sense or if theres a better way.
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can you confirm if this is an OG question or a question from an official GMAC mock?
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Blackcrow1972
Tom travels d miles by a car, whose consumption C gallons per hour is directly proportional to the square of the speed of the car. If he travels 80% of the distance at the speed of 40 miles/hour and the remaining at the speed of 20 miles/hour, he consumes 45 gallons of fuel. How much fuel will he consume if Tom travels the whole distance d miles at the speed of 30 miles hour?

A. 30
B. 37.5
C. 50
D. 60
E. None of these
Could you please provide a screenshot of the question? Thank you!
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It appeared in one of my mocks.
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Blackcrow1972

Tom travels d miles by a car, whose consumption C gallons per hour is directly proportional to the square of the speed of the car. If he travels 80% of the distance at the speed of 40 miles/hour and the remaining at the speed of 20 miles/hour, he consumes 45 gallons of fuel.

How much fuel will he consume if Tom travels the whole distance d miles at the speed of 30 miles hour?

Let C gallons/hour = kv^2 ; where k is a constant and v is speed in miles/hour

Total distance = d miles

@40 miles/hour
Distance = .8d
Time = .8d/40 = .02d hours
Fuel consumption rate C = k(40)^2 = 1600k gallons/hour
Fuel consumption = 1600k*.02d = 32kd

20 miles/hour
Distance = .2d
Time = .2d/20 = .01d
Fuel consumption rate C = k(20)^2 = 400k gallons/hour
Fuel consumption = 400k*.01d = 4kd

Total fuel consumption = 32kd + 4kd = 36kd = 45 gallons
kd = 45/36

@30miles/hour
Distance = d
Time = d/30
Fuel consumption rate C = k(30)^2 = 900k gallons/hour
Fuel consumption = 900k*d/30 = 30kd = 30*45/36 = 37.5 gallons

IMO B
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Which number mock, and was it an official GMAC mock?



Blackcrow1972
It appeared in one of my mocks.
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It appeared in one of my mocks.
Could you please provide a screenshot of the question? Thank you!
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Beautiful problem. Remember the formula for direct proportion and also that fuel consumed= rate of consumption x time:

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C* 0.8d/50 + C* 0.2d/100 = 45
Cd=1500
C* d/30 = 50
why is this approach incorrect?

Blackcrow1972
Tom travels d miles by a car, whose consumption C gallons per hour is directly proportional to the square of the speed of the car. If he travels 80% of the distance at the speed of 40 miles/hour and the remaining at the speed of 20 miles/hour, he consumes 45 gallons of fuel. How much fuel will he consume if Tom travels the whole distance d miles at the speed of 30 miles hour?

A. 30
B. 37.5
C. 50
D. 60
E. None of these
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Blackcrow1972
It appeared in one of my mocks.


Hard to believe. This question cannot be completed in a Reasonable amount of time.
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MartyMurray how can k be the same for each of the speeds?
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Blackcrow1972
Tom travels d miles by a car, whose consumption C gallons per hour is directly proportional to the square of the speed of the car. If he travels 80% of the distance at the speed of 40 miles/hour and the remaining at the speed of 20 miles/hour, he consumes 45 gallons of fuel. How much fuel will he consume if Tom travels the whole distance d miles at the speed of 30 miles hour?

A. 30
B. 37.5
C. 50
D. 60
E. None of these

\(\frac{Consumption}{Speed^2} = Constant\)

\(C = kS^2\) (in gallons/hour)

We are given data of 45 gallons which is consumption in the entire journey, not gallons consumed per hour. Hence we need to find for how many hrs this consumption was maintained.

Comparing Consumption in 80% of the journey with that in 20% of the journey: If distance travelled is 4 times and speed is twice, time taken will be twice too because Time = Distance/Speed

\(C1 = k*40^2 * 2 = 3200k\) gallons (Total consumption in 80% of the journey)
\(C2 = k*20^2 * 1 = 400k\) gallons (Total consumption in 20% of the journey)

Total Consumption = 3600k gallons = 45 gallons (given)

Comparing full journey consumption with that of 20% journey: If distance is 5 times and speed is 3/2, time taken = 10/3 times

\(C3 = k*30^2*\frac{10}{3}*k = 900 * \frac{10}{3} * \frac{45}{3600} = 37.5 gallons\)

Answer (B)

Here is a video on Direct Variation used in this question: https://youtu.be/AT86tjxJ-f0
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