Blackcrow1972
Tom travels d miles by a car, whose consumption C gallons per hour is directly proportional to the square of the speed of the car. If he travels 80% of the distance at the speed of 40 miles/hour and the remaining at the speed of 20 miles/hour, he consumes 45 gallons of fuel. How much fuel will he consume if Tom travels the whole distance d miles at the speed of 30 miles hour?
A. 30
B. 37.5
C. 50
D. 60
E. None of these
\(\frac{Consumption}{Speed^2} = Constant\)
\(C = kS^2\) (in gallons/hour)
We are given data of 45 gallons which is consumption in the entire journey, not gallons consumed per hour. Hence we need to find for how many hrs this consumption was maintained.
Comparing Consumption in 80% of the journey with that in 20% of the journey: If distance travelled is 4 times and speed is twice, time taken will be twice too because Time = Distance/Speed
\(C1 = k*40^2 * 2 = 3200k\) gallons (Total consumption in 80% of the journey)
\(C2 = k*20^2 * 1 = 400k\) gallons (Total consumption in 20% of the journey)
Total Consumption = 3600k gallons = 45 gallons (given)
Comparing full journey consumption with that of 20% journey: If distance is 5 times and speed is 3/2, time taken = 10/3 times
\(C3 = k*30^2*\frac{10}{3}*k = 900 * \frac{10}{3} * \frac{45}{3600} = 37.5 gallons\)
Answer (B)Here is a video on Direct Variation used in this question: https://youtu.be/AT86tjxJ-f0