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26 Aug 2012, 02:59
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
94% (00:42) correct
6%
(01:09)
wrong
based on 3429
sessions
History
Date
Time
Result
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\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}\)
(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3
(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3
26 Aug 2012, 02:59
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SOLUTION:
\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}\)
(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3
\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}= \)
\( =\frac{1}{(\frac{4}{3})}-\frac{1}{(\frac{3}{2})}= \)
\( =\frac{3}{4}-\frac{2}{3}= \)
\( =\frac{1}{12}\).
Answer: D.
\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}\)
(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3
\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}= \)
\( =\frac{1}{(\frac{4}{3})}-\frac{1}{(\frac{3}{2})}= \)
\( =\frac{3}{4}-\frac{2}{3}= \)
\( =\frac{1}{12}\).
Answer: D.
General Discussion
rajathpanta
Joined: 13 Feb 2010
Last visit: 24 Apr 2015
Posts: 144
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Given Kudos: 282
Status:Prevent and prepare. Not repent and repair!!
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Concentration: Technology, General Management
Schools: AGSM '15 YLP '16 IIMC (PGPEX) Melbourne '15
GPA: 3.75
WE:Sales (Telecommunications)
26 Aug 2012, 08:22
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By taking the LCM and taking the reciprocals-
3/4-2/3=1/12
3/4-2/3=1/12
