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If x books cost $5 each and y books cost $8 each, then the average

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carcass
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If x books cost $5 each and y books cost $8 each, then the average [#permalink] New post   Updated on: 21 May 2017, 03:41
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If x books cost $5 each and y books cost $8 each, then the average (arithmetic mean) cost, in dollars per book, is equal to


A) \(\frac{5x+8y}{x+y}\)

B) \(\frac{5x+8y}{xy}\)

C) \(\frac{5x+8y}{13}\)

D) \(\frac{40xy}{x+y}\)

E) \(\frac{40xy}{13}\)
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A

Originally posted by carcass on 21 May 2017, 03:07.
Last edited by Bunuel on 21 May 2017, 03:41, edited 2 times in total.
Renamed the topic.
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Bunuel
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Re: If x books cost $5 each and y books cost $8 each, then the average [#permalink] New post   21 May 2017, 03:44
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carcass wrote:
If x books cost $5 each and y books cost $8 each, then the average (arithmetic mean) cost, in dollars per book, is equal to


A) \(\frac{5x+8y}{x+y}\)

B) \(\frac{5x+8y}{xy}\)

C) \(\frac{5x+8y}{13}\)

D) \(\frac{40xy}{x+y}\)

E) \(\frac{40xy}{13}\)


x books cost $5 each --> total cost of x books = 5x;
y books cost $8 each --> total cost of y books = 8y.

The average cost = (total cost of x + y books)/(number of books) = \(\frac{5x + 8y}{x + y}\).

Answer: A.
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Re: If x books cost $5 each and y books cost $8 each, then the average [#permalink] New post   21 May 2017, 03:56
Here the cost associated with x books is $5 and cost associated with y books is $8.

The total no: of books mentioned is x + y and the total cost associated with it is 5*x + 8*y

Therefore the average cost , in dollars per book is ,

(5*x + 8*y)/(x+y).

Option A is the answer.
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BrentGMATPrepNow
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Re: If x books cost $5 each and y books cost $8 each, then the average [#permalink] New post   26 Aug 2019, 10:37
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carcass wrote:
If x books cost $5 each and y books cost $8 each, then the average (arithmetic mean) cost, in dollars per book, is equal to


A) \(\frac{5x+8y}{x+y}\)

B) \(\frac{5x+8y}{xy}\)

C) \(\frac{5x+8y}{13}\)

D) \(\frac{40xy}{x+y}\)

E) \(\frac{40xy}{13}\)


Average cost per book = (TOTAL cost of all books)/(total number of books)

GIVEN: x books cost $5 each and y books cost $8 each
Cost of x books at $5 apiece = 5x
Cost of y books at $8 apiece = 8y
TOTAL cost of all books = 5x + 8y

TOTAL number of books = x + y

Average cost per book = (5x + 8y)/(x + y)

Answer: A

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Brent
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Re: If x books cost $5 each and y books cost $8 each, then the average [#permalink] New post   27 Aug 2019, 18:35
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carcass wrote:
If x books cost $5 each and y books cost $8 each, then the average (arithmetic mean) cost, in dollars per book, is equal to


A) \(\frac{5x+8y}{x+y}\)

B) \(\frac{5x+8y}{xy}\)

C) \(\frac{5x+8y}{13}\)

D) \(\frac{40xy}{x+y}\)

E) \(\frac{40xy}{13}\)


The average cost of the books is (5x + 8y)/(x + y) dollars.

Answer: A
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Re: If x books cost $5 each and y books cost $8 each, then the average [#permalink] New post   26 Sep 2020, 13:04
CostX=5
CostY=8
Total Cost = 5x + 8y
Boxes = x+y
Avg Cost = (5x+8y)/(x+y)
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Re: If x books cost $5 each and y books cost $8 each, then the average [#permalink] New post   16 Oct 2020, 05:00
Average cost = Sum of the cost / total number of books

= 5x + 3Y / x + y

= Answer A
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Re: If x books cost $5 each and y books cost $8 each, then the average [#permalink] New post   16 Oct 2020, 06:28
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'x' books cost $5 each: Total cost $5x

'y' books cost $8 each: Total cost $8y

Sum: 5x + 8y

Total: x + y

Average (arithmetic mean): \(\frac{(5x + 8y) }{ (x + y)}\)

Answer A
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Re: If x books cost $5 each and y books cost $8 each, then the average [#permalink] New post   06 Jan 2023, 08:53
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: If x books cost $5 each and y books cost $8 each, then the average [#permalink]
06 Jan 2023, 08:53
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