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nick1816
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Statement 1
n/a +n/b =1 and n is integer
That means both are working for n days. It doesn't matter who starts work, work will always finish in 2n days
Sufficient
Statement 2
there are 2 situations possible
1. if n/a +n/b =1 there will be no effect on total duration
2.n/a +n/b is not equal to 1
then work will finish earlier if A will start the work.
Insufficient

nyashka
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A and B work at digging a ditch alternately for a day each. If A can dig a ditch in 'a' days alone and B can dig a ditch in 'b' days alone. Will work be done faster if A begins the work?

1. n is a positive integer such that n[(\(\frac{1}{a})+(\frac{1}{b}\))] = 1
2. b>a


Hello! Could anyone please explain?
Thank you in advance!
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Beautiful question :|
I think the clue here is that n is an integer.
1/x + 1/y = 1/n

x+y=xy/n or n=xy/(x+y);
n=1, x=2, y=2.
n=2, x=4, y=4.
n=4, x=8 y= 8
so no matter who starts first , the work will be completed in the same time.
So x and y have to be of same values for n to be an integer. So , no matter who starts first, it will take the same time.
SUFFICIENT

no definitive ans in the second option as explained by GyanOne.
A can complete 90 percent work in one day and B can complete 20 percent work in one day. Then it will take two days.
A can complete 90 percent work in one day and B can complete 5 percent work in one day. Then it will take three days.
Please give me kudos if you liked my explanation.
INSUFFICIENT
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I think question needs bit of clarity when it says "Will work be done faster if A begins the work"
It does not talk about the number of days it will take to complete the work.
Work will be done faster in A starts as per second Statement as b>a
But if we talk about the number of days it will take to complete the work then second statement is not sufficient.
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One quick way to approach this would be to pick the rate of work for A and B instead of going into algebra

Evaluating statement 2 first since it seems easier
Since b > a, implies that a is faster

Lets say A does 2 units of work per day and B does 1 unit of work per day.
Let total work be 6 unit ---> if a and b are working on alternate days then it wont matter who starts work will finish in 4 days i.e. 2, 1, 2 ,1 units of work done by a starting or 1 , 2 , 1 , 2 done by B starting

However, if the total work is say 5 units

Then if A starts ---> 2 , 1 , 2 ---> full work done in 3 days
But if B starts 1 , 2 , 1 ---> only 4 units done in 3 days hence work will spill over to the 4th day

Hence B is not sufficient

Now coming to statement 1

Notice that this tells you that n is the days since days x units per day = total work
So if the total work is 1, then rates would be 1/a and 1/b and since they are multiplied to give you 1, that means that n is number of days.

But when you look closely what statement 1 tells you. ---> It implies that that when the rates are added together they divide evenly into the total work i.e The total work equals an integer number of complete AB cycles.---> which again means that it wont matter who starts cause the alternate pairs will complete the work in integer integer number of days and there would be no spill over.

Taking our example n(2+1) = 6 ---> this means that n *3 = 6 and we know that n is an integer hence A is sufficient.
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