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such8
Joined: 05 Jul 2019
Last visit: 04 Jan 2021
Posts: 72
Given Kudos: 15
Location: India
Concentration: Strategy, Healthcare
Schools: HEC '22 NUS '22 (D) Marshall '22 (D) ISB '21 (D)
21 Aug 2019, 20:46
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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A student’s average (arithmetic mean) test score on 4 tests is 80. What must be the student’s score on a 5th test for the student’s average score on the 5 tests to be 82?
A. 80
B. 82
C. 90
D. 92
E. 84
A. 80
B. 82
C. 90
D. 92
E. 84
22 Aug 2019, 02:28
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320+X /5=82
So, X=410-320=90
Option C
Posted from my mobile device
So, X=410-320=90
Option C
Posted from my mobile device
Updated on: 17 May 2021, 07:42
Originally posted by BrentGMATPrepNow on 05 Mar 2020, 07:42.
Last edited by BrentGMATPrepNow on 17 May 2021, 07:42, edited 1 time in total.
Last edited by BrentGMATPrepNow on 17 May 2021, 07:42, edited 1 time in total.
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such8
A student’s average (arithmetic mean) test score on 4 tests is 80.
This tells us that: (sum of all 4 scores)/4 = 80
Multiply both sides of the equation by 4 to get: sum of all 4 scores = 320
What must be the student’s score on a 5th test for the student’s average score on the 5 tests to be 82?
This tells us that: (sum of all 5 scores)/5 = 82
Multiply both sides of the equation by 5 to get: sum of all 5 scores = 410
Notice that the sum of all 5 scores is 90 GREATER THAN the sum of all 4 scores
The extra (5th) score must account for this difference
So the fifth score must be 90
Answer: C
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