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08 Mar 2025, 07:24
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
58% (02:25) correct
42%
(02:39)
wrong
based on 110
sessions
History
Date
Time
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Not Attempted Yet
Two trains A and B are running in opposite directions from stations Q and P towards their destinations P and Q respectively. Train A takes 25 hours and Train B takes 36 hours after crossing each other to reach their destinations, If the speed of train A is 108 miles/hr, then find the speed of the other train?
A. 75
B. 120
C. 84
D. 90
E. 96
A. 75
B. 120
C. 84
D. 90
E. 96
08 Mar 2025, 08:04
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Whenever two entities starting from opposite ends at the same time meet at a common point and the total distance they travelled is D, the ratio of their speeds \(\frac{Sa}{Sb} = \sqrt{\frac{Tb}{Ta}}\), where Tb and Ta is the time taken to reach their destination from the common point.
\(\frac{108}{Sb} = \sqrt{\frac{36}{25}}\)
\(\frac{108}{Sb} = \frac{6}{5}\)
\(\frac{18}{Sb} = \frac{1}{5}\)
\(Sb = 5*18 = 90\)
Answer D.
\(\frac{108}{Sb} = \sqrt{\frac{36}{25}}\)
\(\frac{108}{Sb} = \frac{6}{5}\)
\(\frac{18}{Sb} = \frac{1}{5}\)
\(Sb = 5*18 = 90\)
Answer D.
General Discussion
15 Mar 2025, 02:04
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Helo, thanks for sharing the solution!
Is this tested on GMAT? I found no reference to this formula on TTP. Also, could you please explain how the formula could be derived?
Is this tested on GMAT? I found no reference to this formula on TTP. Also, could you please explain how the formula could be derived?
Krunaal
