Explanation:
Given that a and b are positive integers. ⇒ a + b and a − b will also be integers
Considering statement 1:
a2 − b2 = 169
⇒ (a − b)(a + b) = 169 = 13 × 13
Now there are 4 possibilities for a + b and a − b: 1, 169 or 13, 13 or −1, −169 or −13, −13.
Case 1:
a + b = 169 and a − b = 1
Solving 2 equations => a = 85 and b = 84
Case 2:
a + b = 13 and a − b = 13
Solving 2 equations ⇒ a = 13 and b = 0
Since a and b are positive integers, so these values can be rejected.
Case 3:
a + b = −1 and a − b = −169
Solving 2 equations ⇒ a = −85 and b = −84
Since a and b are positive integers, so these values can be rejected.
Case 4:
a + b = −13 and a − b = −13
Solving 2 equations ⇒ a = −13 and b = 0
Since a and b are positive integers, so these values can be rejected.
Since we are getting a definite answer from above statement (only Case 1), statement 1 itself is sufficient to provide the answer.
Considering statement 2:
a − b =1
As only known information is that a and b are positive integers , infinite values of a and b are possible for which a − b =1.
Since we are not getting a definite answer from above statement , statement 2 also itself is not sufficient to provide the answer.
Answer: A