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24 Aug 2011, 05:04
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
78% (01:34) correct
22%
(02:17)
wrong
based on 821
sessions
History
Date
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Salad dressing A is made up of 30% vinegar and 70% oil, and salad dressing B contains 10% vinegar and 90% oil. If the 2 dressing are combined to produce a salad dressing that is 15% vinegar, dressing A comprises what % of the new dressing?
A. 15%
B. 20%
C. 25%
D. 40%
E. 55%
A. 15%
B. 20%
C. 25%
D. 40%
E. 55%
24 Aug 2011, 07:07
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There is one trick you can use to solve mixture problems very fast.
quantity of Vinegar in A: 30%, in B: 10% and in (A+B): 15%
We need (15-10)/(30-10) = 5/20 = 1/4 or 25% of A.
quantity of Vinegar in A: 30%, in B: 10% and in (A+B): 15%
We need (15-10)/(30-10) = 5/20 = 1/4 or 25% of A.
24 Aug 2011, 06:53
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they way I solved it:
quantity of Vinegar => 30% A + 10% B = 15% (A + B)
30%A + 10%B = 15%A + 15%B
15%A = 5%B
B = 15%A / 5% = 3A
if B = 3A => A+B = 4A
as a result A / (A+B) = A / 4A = 0.25 = 25%
quantity of Vinegar => 30% A + 10% B = 15% (A + B)
30%A + 10%B = 15%A + 15%B
15%A = 5%B
B = 15%A / 5% = 3A
if B = 3A => A+B = 4A
as a result A / (A+B) = A / 4A = 0.25 = 25%
