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rdevorse
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why are we not considering 0 for c?
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why are we not considering 0 for c?

If \(c=0=even\) then \(abc=0=even\), so III holds true for this particular value of \(c\) as well.
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rdevorse
If a, b, and c are integer and ab + c is odd, which of the must be true?

I. a + c is odd
II. b + c is odd
III. abc is even

(A) I only
(B) II only
(C) III only
(D) I and III only
(E) II and III only

I understand the reasoning behind the correct answer, but the MGMAT book's solution also uses a graph which I cannot understand (please see attached file). Can someone explain why under both a and b in the row for two, it is listed as Odd, and then Even for the c column? The book doesn't explain how it sets up the graph.

Thanks


Hi guys,
Can we just do this by substituting,
like I take say a=1,b=2 and c= 3 which gives ab+c = 5 , holds true for b+c is odd and abc is odd
Secondly a=2,b=5 and c=7 gives ab+c=17, holds true for a+c is odd and abc is odd.
Considering both we come to a conclusion that abc is odd alone.
Hope that helps!
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