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phoenix9801
Hello, Unfortunately the book did not provide any solution. Hence I have no I was correct or not. Can someone show me how it is done please. thanks.

Local kennel has cats and dogs in the ratio of 5:6. If there are 18 fewer cats than dogs, how many dogs are in the kennel?

A. 60
B. 74
C. 98
D. 108
E. 132

Given: \(\frac{cats}{dogs}=\frac{5x}{6x}\), for some positive multiple \(x\).

Also: \(dogs-cats=6x-5x=18\) --> \(x=18\) --> \(dogs=6x=108\).

Answer: D.
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phoenix9801
Hello, Unfortunately the book did not provide any solution. Hence I have no I was correct or not. Can someone show me how it is done please. thanks.

Local kennel has cats and dogs in the ratio of 5:6. If there are 18 fewer cats than dogs, how many dogs are in the kennel?

A. 60
B. 74
C. 98
D. 108
E. 132

1 represents 18

So, Number of dogs is 18*6 = 108, Answer must be (D)
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phoenix9801
Hello, Unfortunately the book did not provide any solution. Hence I have no I was correct or not. Can someone show me how it is done please. thanks.

Local kennel has cats and dogs in the ratio of 5:6. If there are 18 fewer cats than dogs, how many dogs are in the kennel?

A. 60
B. 74
C. 98
D. 108
E. 132

let d=dogs in kennel
d/(d-18)=6/5
d=108
D
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Let the number of cats be \(x\)

Let the number of dogs be \(y\)Since Local kennel has cats and dogs in the ratio of 5:6, \(\frac{x}{y}\)= \(\frac{5}{6}\)

\(6x = 5y\)

Since, there are 18 fewer cats than dogs,\(y - 18 = x\)

\(y = 18 + x\)

\(6x = 5( 18 + x )\)

\(6x = 90 + 5x\)

\(x = 90\)

\(6 * 90 = 5y\)

\(y = 18 * 6 = 108\)

The correct answer is D
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phoenix9801
Hello, Unfortunately the book did not provide any solution. Hence I have no I was correct or not. Can someone show me how it is done please. thanks.

Local kennel has cats and dogs in the ratio of 5:6. If there are 18 fewer cats than dogs, how many dogs are in the kennel?

A. 60
B. 74
C. 98
D. 108
E. 132

We can express the ratio of cats to dogs as 5x : 6x. We can create the equation:

6x - 5x = 18

x = 18

Thus, there are 6 x 18 =108 dogs in the kennel.

Answer: D
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phoenix9801
Hello, Unfortunately the book did not provide any solution. Hence I have no I was correct or not. Can someone show me how it is done please. thanks.

Local kennel has cats and dogs in the ratio of 5:6. If there are 18 fewer cats than dogs, how many dogs are in the kennel?

A. 60
B. 74
C. 98
D. 108
E. 132

We can express the ratio of cats to dogs as 5x : 6x. We can create the equation:

6x - 5x = 18

x = 18

Thus, there are 6 x 18 =108 dogs in the kennel.

Answer: D

X/X+18 =5/6
6X-5X=90
X=90,X+18=108
Option D

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phoenix9801

Local kennel has cats and dogs in the ratio of 5:6. If there are 18 fewer cats than dogs, how many dogs are in the kennel?

A. 60
B. 74
C. 98
D. 108
E. 132

Let D = # of Dogs
Let C = # of Cats


There are 18 fewer cats than dogs.
So, C = D - 18

cats and dogs are in the ratio of 5:6
We get: C/D = 5/6
Cross multiply to get: 6C =5D

Take 6C =5D and replace C with D - 18 to get: 6(D - 18) = 5D
Expand: 6D - 108 = 5D
Subtract 6D from both sides to get: -108 = -D
So, D = 108

Answer: D

Cheers,
Brent
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phoenix9801
Hello, Unfortunately the book did not provide any solution. Hence I have no I was correct or not. Can someone show me how it is done please. thanks.

Local kennel has cats and dogs in the ratio of 5:6. If there are 18 fewer cats than dogs, how many dogs are in the kennel?

A. 60
B. 74
C. 98
D. 108
E. 132

given ration c/d = 5/6
and c= d-18
solve for d
imo D ; 108
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