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rohitkg
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Nice application. Watch out for the typo in e & f.
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As someone with a degree in Computer Science who owns several binary clocks (seriously I own more than one... it's a little weird!), I will say: Kudos. As pointed out above, you have slight typos in e) and f) regarding which term is even and which term is odd. I'd also be remiss if I didn't mention that this works just as well using the numbers 1 and 0 in non-binary applications. 0x1 is still 1, 0+0 is still 0. The only difference is 1+1 = 2, which is even. In actuality, you can just use odd or even number to prove the rule without ever having to reference binary.

Nonetheless, I find it useful and insightful to think about in terms of number properties. And if it works well for you and others, then good job taking something abstract and making it familiar with terms you already know well. Good job!

Ron
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vandygrad11
Nice application. Watch out for the typo in e & f.

Thanks for informing :-D ... rectified the typo :)
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This is awesome, thank you!!

As someone not familiar with binary, can you explain 1 + 1 = 10?


Also, anyone know other places to find tricks like these?
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aceon
This is awesome, thank you!!

As someone not familiar with binary, can you explain 1 + 1 = 10?


Also, anyone know other places to find tricks like these?

Our Math Book is full of them: gmat-math-book-87417.html

Hope it helps.
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thanks for this useful shortcut!!!

substraction is just llike addition

But, do you think it could be used for division somehow??
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nicoki
thanks for this useful shortcut!!!

substraction is just llike addition

But, do you think it could be used for division somehow??


Hi Nicoki,

There is no rule as such for division of 'odd or even numbers' :-D . Cause result can be fraction too in such cases.
Don't worry no one will ask you question based on Division. Atleast I have never come across any such question.

Best Regards,
Rohit Gupta
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good stuff .... thanks for sharing
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rohitkg
I have formulated a technique to solve type of 'Odd and Even number type questions' quickly, thus saving ample amount of time for other questions.
Basic concept used is of binary number calculations.

Binary Multiplication
0 * 0 = 0, 1 * 0 = 0, 1 * 0 = 0, 1 * 1 = 1

Binary Addition
0 + 0 = 0, 1 + 0 = 1, 0 + 1 = 1
1 + 1 = 10 or 0 [For applying the technique we need to consider last digit of ‘10’ i.e. ‘0’]

Application of Technique
Odd Number => 1
Even Numbers => 0

a. Odd Number * Odd Number = Odd number
1 * 1 = 1

b. Odd Number * Even Number = Even Number
1 * 0 = 0

c. Even Number * Even Number = Even Number
0 * 0 = 0

d. Odd Number + Odd Number = Even Number
1 + 1 = 0

e. Even Number + Odd Number = Odd Number
0 + 1 = 1

f. Even Number + Even Number = Even Number
0 + 0 = 0


Usage in Exam
Ex:

Solve (odd + (even * even * (odd + even) + odd * (even +even)) +even *odd) ?
Solution: (1 + ( 0 * 0 * ( 1 + 0 ) + 1 * ( 0 + 0 )) + 0 * 1 )
= (1 + ( 0 * 1 +0 ) + 0)
= (1 + 0 + 0)
= 1 =>(Odd)

This equation can be solved mentally within 15secs.
This technique has helped me in solving these types of question within 30 seconds with practice and hence saving a lot of time.


rohitkg..... Amazing.. U just made my life easier. Kudos
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