Last visit was: 23 Apr 2026, 03:23 It is currently 23 Apr 2026, 03:23
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Chetangupta
Joined: 23 Jan 2011
Last visit: 04 Oct 2021
Posts: 82
Own Kudos:
484
 [72]
Given Kudos: 13
Posts: 82
Kudos: 484
 [72]
3
Kudos
Add Kudos
69
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
ayushman
Joined: 22 Oct 2013
Last visit: 28 Aug 2015
Posts: 54
Own Kudos:
78
 [34]
Given Kudos: 10
GMAT 1: 750 Q50 V42
GMAT 1: 750 Q50 V42
Posts: 54
Kudos: 78
 [34]
18
Kudos
Add Kudos
16
Bookmarks
Bookmark this Post
General Discussion
avatar
SaraLotfy
Joined: 24 Apr 2013
Last visit: 28 Oct 2013
Posts: 43
Own Kudos:
31
 [4]
Given Kudos: 23
Location: United States
Posts: 43
Kudos: 31
 [4]
4
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
ayushman
Joined: 22 Oct 2013
Last visit: 28 Aug 2015
Posts: 54
Own Kudos:
Given Kudos: 10
GMAT 1: 750 Q50 V42
GMAT 1: 750 Q50 V42
Posts: 54
Kudos: 78
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Thanks Chetan. Yes, I feel slightly less miserable in Maths than I do in Verbal:)
User avatar
CEdward
Joined: 11 Aug 2020
Last visit: 14 Apr 2022
Posts: 1,162
Own Kudos:
Given Kudos: 332
Posts: 1,162
Kudos: 289
Kudos
Add Kudos
Bookmarks
Bookmark this Post
ayushman
The events A and B are independent, the probability that event A occurs is greater than 0, and the probability that event A occurs is twice the probability that event B occurs. The probability that at least one of events A and B occurs is 8 times the probability that both events A and B occur. What is the probability that event A occurs?

Let us say probability of A occuring is a.
Let us say probability of B occuring is b.

a = 2b

Probability (either A or B or both) = 8 times Probability (A and B)
a*(1-b) + b*(1-a) + ab = 8*ab

Substituting a=2b in the second equation:

2b*(1-b) + b*(1-2b) + 2b*b = 8*2b*b

3b-2b^2 = 16b^2
3b = 18b^2
b = 3/18 = 1/6

So, a = 2b = 1/3

I was oh so close to solving. If anyone sees, can you explain why Probability (either A or B or both) =
a*(1-b) + b*(1-a) + ab? I get the 'ab' part, but why is it a*(1 - b) + b*(1-a)?
avatar
mba757
avatar
Current Student
Joined: 15 Jun 2020
Last visit: 04 Aug 2022
Posts: 295
Own Kudos:
Given Kudos: 245
Location: United States
GPA: 3.3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi Bunuel,

Could you please explain the logic behind the answer key? I understand that we use x for P(b) and 2x for P(a). However, given that the problem states that "at least one of events A and B occurs is 8 times the probability that both events A and B occur..", how can the OA state that you can just use the formula P(a) + P(b) - P(a and b)? The "at least one" would encompass not only the probability of JUST a (and JUST b) but also the probability of both. Thus, it should be P(a) and P(b) - P(a and b) = 8[P(a and b)].

What am I missing here?
avatar
mba757
avatar
Current Student
Joined: 15 Jun 2020
Last visit: 04 Aug 2022
Posts: 295
Own Kudos:
97
 [4]
Given Kudos: 245
Location: United States
GPA: 3.3
2
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
OA:

"Approach Strategically:

Let A and B be events. Let P(A) be the probability that event A occurs, let P(B) be the probability that event B occurs, let P(A or B) be the probability that at least one of the events A and B occurs, and let P(A and B) be the probability that both events A and B occur. The formula to calculate the probability that at least one event occurs is P(A or B) = P(A) + P(B) − P(A and B), (note that you cannot just add the two probabilities together). When the events A and B are independent, P(A and B) = P(A)P(B). So when the events A and B are independent, the formula for the probability that at least one of the events A and B occurs is P(A or B) = P(A) + P(B) − P(A)P(B).

Since the events A and B are independent, the probability that both of the events A and B occur is (2x)(x) = 2x2. Then the probability that at least one of the events A and B occurs is 2x + x − (2x)(x) = 3x − 2x2. Since the probability that at least one of the events A and B occurs is 8 times the probability that both of the events A and B occur, we have the equation 3x − 2x2 = 8(2x2). Let's solve this equation for x. We have 3x − 2x2 = 16x2, 3x = 18x2, x = 6x2. Since x is positive, we can divide both sides of the equation x = 6x2 by x. Then 1 = 6x. Dividing both sides of the equation 1 = 6x by 6, we have . Now we want the probability that event A occurs, which is 2x. The probability that event A occurs is . Answer Choice (D) is correct."
User avatar
rsrighosh
Joined: 13 Jun 2019
Last visit: 11 Dec 2022
Posts: 184
Own Kudos:
Given Kudos: 645
GMAT 1: 490 Q42 V17
GMAT 2: 550 Q39 V27
GMAT 3: 630 Q49 V27
GMAT 3: 630 Q49 V27
Posts: 184
Kudos: 137
Kudos
Add Kudos
Bookmarks
Bookmark this Post
VeritasKarishma chetan2u Bunuel

What do we mean by at least one of events A and B occurs

P(A∪B) = means P(A) or P(B) but not P(A∩B) = P(A) + P(B) - P(A∩B)--> does this mean at least one of events A and B occurs ?

Because I was approaching to a wrong answer by doing P(A) + P(B) + P(A∩B) thinking that at least meant either P(A) or P(B) or both P(A)&P(B)

However doing P(A∩B) = P(A) + P(B) - P(A∩B) gave me the correct answer.
User avatar
andreagonzalez2k
Joined: 15 Feb 2021
Last visit: 26 Jul 2025
Posts: 308
Own Kudos:
Given Kudos: 14
Posts: 308
Kudos: 503
Kudos
Add Kudos
Bookmarks
Bookmark this Post
rsrighosh
VeritasKarishma chetan2u Bunuel

What do we mean by at least one of events A and B occurs

P(A∪B) = means P(A) or P(B) but not P(A∩B) = P(A) + P(B) - P(A∩B)--> does this mean at least one of events A and B occurs ?

Because I was approaching to a wrong answer by doing P(A) + P(B) + P(A∩B) thinking that at least meant either P(A) or P(B) or both P(A)&P(B)

However doing P(A∩B) = P(A) + P(B) - P(A∩B) gave me the correct answer.

At least one of events A and B occurs means P(A∪B).
A∪B means A or B INCLUDING A∩B

In the formula:
P(A∪B) = P(A) + P(B) - P(A∩B)

you must subtract "P(A∩B)" because when you add "P(A) + P(B)" you are adding "P(A∩B)" twice. It is easy to understand it if you draw a Venn diagram.
User avatar
KarishmaB
Joined: 16 Oct 2010
Last visit: 22 Apr 2026
Posts: 16,441
Own Kudos:
79,393
 [3]
Given Kudos: 484
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,441
Kudos: 79,393
 [3]
3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
rsrighosh
VeritasKarishma chetan2u Bunuel

What do we mean by at least one of events A and B occurs

P(A∪B) = means P(A) or P(B) but not P(A∩B) = P(A) + P(B) - P(A∩B)--> does this mean at least one of events A and B occurs ?

Because I was approaching to a wrong answer by doing P(A) + P(B) + P(A∩B) thinking that at least meant either P(A) or P(B) or both P(A)&P(B)

However doing P(A∩B) = P(A) + P(B) - P(A∩B) gave me the correct answer.

P(A∪B) means A occurs or B occurs or both occur.

P(A∪B) = P(A) + P(B) - P(A∩B)

Note that the minus sign above subtracts out P(A∩B) because P(A∩B) is counted two times. P(A∩B) is a part of P(A) and P(A∩B) is also a part of P(B). So you subtract it out to count it only once. After subtracting P(A∩B), P(A∩B) is still included in P(A∪B).

In other words,
P(A) = P(Only A) + P(A∩B)
and
P(B) = P(Only B) + P(A∩B)

So P(A∪B) = P(A) + P(B) - P(A∩B) = P(Only A) + P(A∩B) + P(Only B) + P(A∩B) - P(A∩B)
P(A∪B) = P(Only A) + P(A∩B) + P(Only B)

So P(A∪B) includes only event A occurs, only event B occurs and Both occur.
User avatar
ThatDudeKnows
Joined: 11 May 2022
Last visit: 27 Jun 2024
Posts: 1,070
Own Kudos:
1,030
 [1]
Given Kudos: 79
Expert
Expert reply
Posts: 1,070
Kudos: 1,030
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Chetangupta
The events A and B are independent, the probability that event A occurs is greater than 0, and the probability that event A occurs is twice the probability that event B occurs. The probability that at least one of events A and B occurs is 8 times the probability that both events A and B occur. What is the probability that event A occurs?

A. 1/12
B. 1/8
C. 1/6
D. 1/3
E. 2/3

I prefer Plugging In The Answers PITA over algebra...usually just as fast and usually a lower risk of making a silly mistake.
I usually like trying B and D and tend to pick whichever of those looks easier to work with. In this case (lucky...?), that's D.

D:
A=1/3. B=1/6.
At least one of A and B = 1-notAandnotB = 1-(2/3)(5/6) = 1-(10/18) = 8/18
Both A and B = (1/3)(1/6) = 1/18
Is that what we wanted? Yep.

Answer choice D.
User avatar
Purnank
Joined: 05 Jan 2024
Last visit: 18 Apr 2026
Posts: 680
Own Kudos:
Given Kudos: 167
Location: India
Concentration: General Management, Strategy
GMAT Focus 1: 635 Q88 V76 DI80
Products:
GMAT Focus 1: 635 Q88 V76 DI80
Posts: 680
Kudos: 614
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Chetangupta
The events A and B are independent, the probability that event A occurs is greater than 0, and the probability that event A occurs is twice the probability that event B occurs. The probability that at least one of events A and B occurs is 8 times the probability that both events A and B occur. What is the probability that event A occurs?

A. 1/12
B. 1/8
C. 1/6
D. 1/3
E. 2/3
A > 0 and A = 2B
Quote:
The probability that at least one of events A and B occurs is 8 times the probability that both events A and B occur. What is the probability that event A occurs?
AUB = 8*A∩B
But AUB = A + B - A∩B

9A∩B = A + B = 2B + B = 3B

Also A and B are independent,
Therefore A∩B = A*B
9A*B = 3B

\(A = \frac{1}{3}\)

Answer is D.
User avatar
sarthak1701
Joined: 11 Sep 2024
Last visit: 14 Apr 2026
Posts: 108
Own Kudos:
Given Kudos: 18
GMAT Focus 1: 575 Q77 V81 DI78
GMAT Focus 1: 575 Q77 V81 DI78
Posts: 108
Kudos: 65
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Let P (A) = a, Let P (B) = b

a = 2b, since we need to find a, let us substitute b, b = a/2

At least one occurs is equal to 8 times both occur.

Let us put this in equations.

At least occurs = 1 - none occurs

None occurs = (1-a)(1-b) = (1-a)(1-a/2) = (a^2-3a-2)/2

At least one occurs = 1 - (a^2-3a-2)/2

Now this is equal to 8ab = 8a * a/2 = 4a^2

Substituting and solving we get

a = 3a^2

a = 1/3
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,959
Own Kudos:
Posts: 38,959
Kudos: 1,117
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109773 posts
Tuck School Moderator
853 posts