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06 Jun 2014, 00:36
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
76% (02:01) correct
24%
(02:47)
wrong
based on 472
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In Sam’s chemistry class, his final grade consists of lab work and the final exam. If lab work is 2/3 of the final grade, and he scores 80%, what must he score on the final exam to earn a final grade of 75%?
A. 65%
B. 68%
C. 70%
D. 73%
E. 75%
A. 65%
B. 68%
C. 70%
D. 73%
E. 75%
06 Jun 2014, 01:19
Kudos
Bookmarks
Answer = A = 65%
Let the total final marks (Lab + Exam) = 300 (Out of marks)
Lab is \(\frac{2}{3}\) rd, so exam would be \(\frac{1}{3}\)rd
Setting up the table as below
Lab .............. Exam ................. Final
200 ................ 100 ...................... 300 (This are the max. marks for which exam is conducted)
Has got 80% in Lab & requires 75% in final
80% of 200 = 160; 75% of 300 = 225
160 ................. x ............................ 225
So marks required in Exam (x)
= 225 - 160
= 65%
Let the total final marks (Lab + Exam) = 300 (Out of marks)
Lab is \(\frac{2}{3}\) rd, so exam would be \(\frac{1}{3}\)rd
Setting up the table as below
Lab .............. Exam ................. Final
200 ................ 100 ...................... 300 (This are the max. marks for which exam is conducted)
Has got 80% in Lab & requires 75% in final
80% of 200 = 160; 75% of 300 = 225
160 ................. x ............................ 225
So marks required in Exam (x)
= 225 - 160
= 65%
General Discussion
06 Jun 2014, 01:31
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nidhi12
Sol: If you are good with weighted average concept then it shouldn't take you long
Here is how I would approach this problem.
Attachment:
Untitled.png [ 6.65 KiB | Viewed 6635 times ]
It is given that Lab work exam has 2/3 weightage and final exam therefore will have weightage of 1/3
Therefore by weighted average ratio.
The final grade score of 75% will be twice as close to Lab exam average then final exam average
Now If total distance between Final exam and Lab exam is x
then x/3 will be distance between Lab exam score and Total final grade score and
2x/3 will be distance between final exam score and Total final grade score
Given x/3 =5 so x= 15
and therefore 2x/3 =10. So Final exam score will be 10 less than grade score of percentage of 75 ie. 75-10= 65%
Ans is A.
Another way to do it will be
\(\frac{W1}{W2}\)= \(\frac{(A2- Avg)}{(Avg- A1)}\)
W1=1/3
W2=2/3
So W1/W2= 1/2
\(\frac{1}{2}\) = \(\frac{(80-75)}{(75-x)}\)
1/2 = 5/(75-x)
75-x=10 or x =65%
For more on weighted average concept..Check out Veritas prep blog:
https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2011/04 ... ge-brutes/
https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2011/03 ... -averages/
