Official Solution: A ship is carrying several cats, along with a crew consisting of sailors, a cook, and a one-legged captain, to a nearby port. If the crew and cats collectively have 15 heads and 41 legs, how many cats are on the ship? A. 3
B. 5
C. 6
D. 7
E. 8
Excluding the cook, the remaining passengers — cats, sailors, and the one-legged captain — collectively have 14 heads and 39 legs.
Excluding the one-legged captain, the remaining passengers — cats and sailors — collectively have 13 heads and 38 legs.
Let's assume there are \(x\) cats and \(13 - x\) sailors. Consequently, we can set up the equation \(4*x + 2*(13 - x) = 38\), which gives \(x=6\).
Another way to solve this question is via Backsolving:
1. We know that we have 1 cook and 1-legged captain, removing them from the totals, leaves us with 38 legs (out of 41 starting legs) and 13 heads (out of 15 starting heads). Things are a bit clearer now.
2. Now we can pick 7 cats and try if this makes the puzzle work - that would be 7 heads and 28 legs, plus 5 sailors (38-28 legs gives us that) But the heads do not match, we need 13 heads but 7+5 is only 12. Thus likely need a smaller number of cats, which they have a 2:1 relationship with humans, so removing 1 cat will give us 2 sailors.
3. Picking 6 cats, give us 24 legs, and then 38-24 = 14 sailor legs or 7 sailors with 7 heads. This means 13 heads, which matches our totals.
Answer: C