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Bunuel
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Bunuel
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I used the concept of trailing zeroes as the last digits are ....0013 we can see that it is not divisible by any no. other than it self.
I am doubtfull whether it was mere luck in the question or is this way of doing it is also correct?
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piyuusshh
I used the concept of trailing zeroes as the last digits are ....0013 we can see that it is not divisible by any no. other than it self.
I am doubtfull whether it was mere luck in the question or is this way of doing it is also correct?

15! + 13 = ...013 (actually it's 1,307,674,368,013)

Since the last digit is 3 (odd) we can get that it's not divisible by any even number (eliminate B and E) and not divisible by 5 because it does not end with 0 or 5 (eliminate A). But a number ending with 13 may or may not be divisible by 7 and may or may not be divisible by 13. For example, 413 is divisible by 7 and not divisible by 13.
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I solved it in the following method. It might be slightly more involved than Bunuel's solution.

\(n=15!+13\)
Let \(x\) be the divisor.

\(\frac{n}{x} = \frac{(15!+13)}{x}\)
\(\frac{n}{x} = \frac{15!}{x}+ \frac{13}{x}\)
The only value where \(\frac{n}{x}\) is an integer is where \(x = 13\).
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I think this is a high-quality question and I agree with explanation.
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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I like the solution - it’s helpful.
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I like the solution - it’s helpful.
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I like the solution - it’s helpful.
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I like the solution - it’s helpful.
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I like the solution - it’s helpful.
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I did not quite understand the solution. How would I know that 15! is divisible by 13??
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facilisomnis
I did not quite understand the solution. How would I know that 15! is divisible by 13??
Because 15! means the product of all integers from 1 to 15, inclusive:

15! = 1 * 2 * 3 * ... * 12 * 13 * 14 * 15

Since 13 is one of the numbers in this product, 15! automatically includes 13 as a factor. That makes 15! divisible by 13.

In general, n! is always divisible by every integer k where 1 ≤ k ≤ n.
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I like the solution - it’s helpful.
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I like the solution - it’s helpful.
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I did not quite understand the solution. how exactly do you actually know that 13 is the factor of 15!
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Priyanshu7297
I did not quite understand the solution. how exactly do you actually know that 13 is the factor of 15!

Explained here: https://gmatclub.com/forum/m03-183605.html#p3631735 Hope it helps.
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