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How do we reduce the distance in the equation from d to 1?

Since d is an unknown it can be 1 or 2 or 3 hours, etc.
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How do we reduce the distance in the equation from d to 1?

Since d is an unknown it can be 1 or 2 or 3 hours, etc.

We are reducing the fraction by common term. You can factor out d both from the denominator and numerator and then reduce.

\(\frac{d+d}{\frac{d}{60}+\frac{d}{x}}=\frac{2d}{d*(\frac{1}{60}+\frac{1}{x})}=\frac{2}{\frac{1}{60}+\frac{1}{x}}\).

Hope it's clear.
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The distance/rate eqation is: distance = rate * time. We are trying to find rate, so change it to: distance/time = rate

D/T1 = 60
D/T2 = R2
(2D)/(T1+T2) = Average Rate

Just to make the problem easier let's just say that the distance is 100 miles. This will make T1 = 5/3. Average rate will equal 200/(5/3 + T2). We can find average rate as long as we find T2, or the amount of time it took for the evening trip.

1) R2 = 40.
If R2 = 40 and D = 100 then you can find T2. T2 will be 5/2. With T2 you can find average rate which will be 200/(5/3+5/2) = 200/(13/3) = 600/13 which is about 46.15 mph

2) T1 = 2
With T1 we can find the actual D but we still don't know T2. Insufficient.

Answer is A.
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Bought gmat club tests so that I could have explanations I could get grasp for such problems. May be it's my current level of quant, but I wasn't able to get the explanations for this problem at all.

Can anyone please help explain this step by step how this can be best solved?
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nust2017
Bought gmat club tests so that I could have explanations I could get grasp for such problems. May be it's my current level of quant, but I wasn't able to get the explanations for this problem at all.

Can anyone please help explain this step by step how this can be best solved?

The question is not that hard. The explanation provided above is clear and simple. So, if you cannot get it AT ALL, then it might be a good idea to go through basics and only then practice the questions.


16. Distance/Rate Problems



For more check below:
ALL YOU NEED FOR QUANT ! ! !
Ultimate GMAT Quantitative Megathread
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Bunuel
In the morning, John drove to his mother's house in the village at an average speed of 60 kilometers per hour. When he was going back to town in the evening, he drove more cautiously and his speed was lower. If John went the same distance in the evening as in the morning, what was John's average speed for the entire trip?


(1) In the evening, John drove at a constant speed of 40 kmh.

(2) John's morning drive lasted 2 hours.

formula to find avg speed when distance travelled is same:
2ab/ (a+b)

so
here we are given onward speed @ 60 kmph
and
#1
return speed @40kmph
avg speed : 2 * 60*40 / 100 = 48 kmph
sufficeint
#2

time of drive given ; in sufficient

IMO A
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Will the average speed be 48 kmph considering speed from the village to town is 40 kmph?
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Will the average speed be 48 kmph considering speed from the village to town is 40 kmph?

Yes, 2/(1/60 + 1/40) = 48.
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I think this is a high-quality question and I agree with explanation.
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I think this is a high-quality question and I agree with explanation.
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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You can simply try solving with two different distances, for example, 100 and 200. In both cases with statement (1) you will get the answer 48. So (1) is sufficient.
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from (2) can't we find the distance?
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from (2) can't we find the distance?

We can, but it doesn’t help. All (2) gives is that the distance from town to the village is 60 * 2 = 120 km. But we still know nothing about the evening drive, so we can’t determine the average speed. And in fact, the actual distance isn’t even needed, since it cancels in the formula. So this information is basically useless.
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I like the solution - it’s helpful.
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