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Bunuel
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Bunuel
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In order to be divisible by 18, an integer has to be divisible both by 2 and 9. The integer above ending by 8, the unit digit will be an 8 no matter the value of exponent n and thus divisible by 2. An integer is divisible by 9 when the sum of its digits is divisible by 9. The sum of the digits of 10 power of n +8 will always be 9 for n an integer greater than 1. The only value for which it would not work is when n=0. That’s why « (2) n is an even number » is not satisfactory. The right answer is (A)
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I think this is a high-quality question and I agree with explanation.
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