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glochou
Can someone show the math that proves that A+B = 4x as fast as A alone? I conceptually understand (I think) but it would be nice to see the numbers work out.

A does 1 unit of work in the same time as B does 3 units of work. Thus together they do 4 units of work in the same time interval.
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A= 36hrs
B= three times more efficient than A = 36/3=12 Hrs

1/2 the work is already completed because A has done work for 18hrs

so equ will be

Rate * t= work
(1/36+1/12)t = 1/2

t=4.5 Hrs

18+4.5 =22.5 Hrs
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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I think this is a high-quality question and I agree with explanation.
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The time taken by A to finish half of the task ( data processing) = 18 hours ;
Now we have to find the time taken by A and B together to  complete the task to understand their combined efficiency.
1/36 + 1/12 = 1/9 [ B is thrice as efficient as A in completing the task --> 36 hours / 3 = 12 hours ]

So, in order to complete remaining data processing they will take 9 hours / 2 = 4.5 hours.

So, the total time taken is 18 hours + 4.5 hours = 22.5 hours.

Answer is 5:30 pm, Tuesday
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