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16 Sep 2014, 01:05
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B
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Difficulty:
15%
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Question Stats:
80% (01:13) correct
20%
(01:20)
wrong
based on 188
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A casino offers chips in denominations of $10, $25, $50, and $100. If a player wishes to place a bet of $165, what is the minimum number of chips he needs to use?
A. 5
B. 6
C. 7
D. 8
E. 10
A. 5
B. 6
C. 7
D. 8
E. 10
16 Sep 2014, 01:05
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Official Solution:
A casino offers chips in denominations of $10, $25, $50, and $100. If a player wishes to place a bet of $165, what is the minimum number of chips he needs to use?
A. 5
B. 6
C. 7
D. 8
E. 10
To achieve a $165 bet with the fewest chips, first subtract the sole denomination containing a '5', which is 1 $25 chip. For the remaining $140, maximize the use of the largest denomination, utilizing 1 $100 chip. The balance can be covered with 4 $10 chips. Thus, the optimal combination is \(1*100 + 1*25 + 4*10 = 165\), requiring a total of 1 + 1 + 4 = 6 chips.
Answer: B
A casino offers chips in denominations of $10, $25, $50, and $100. If a player wishes to place a bet of $165, what is the minimum number of chips he needs to use?
A. 5
B. 6
C. 7
D. 8
E. 10
To achieve a $165 bet with the fewest chips, first subtract the sole denomination containing a '5', which is 1 $25 chip. For the remaining $140, maximize the use of the largest denomination, utilizing 1 $100 chip. The balance can be covered with 4 $10 chips. Thus, the optimal combination is \(1*100 + 1*25 + 4*10 = 165\), requiring a total of 1 + 1 + 4 = 6 chips.
Answer: B
31 Jul 2017, 06:07
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Bunuel
At first subtract the only term containing 5 i.e. 25, then to make the remaining 140 by minimum possible means we need 1* 100 + 4*10.
Hence total no of bets = 1+4+1=6
