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Harley1980
Is yz > x?

(1) y > x/z
(2) z < 0


Is yz > x?

(1) y > x/z
(2) z < 0

(1) y > x/z
y-x/z > 0
(yz-x)/z > 0

2 cases:
a) yz-x>0 and z>0 in which case YES yz>x.
b) yz-x < 0 and z<0 in which case yz<x.

Not sufficient.

2) z<0 .
no info about y ,x
Not sufficient.

together:
if z<0 then yz-x < 0 in which case yz<x.

sufficient.

The answer of this task is C . And optimal time for this task is 90 seconds.
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Harley1980
Is yz > x?

(1) y > x/z
(2) z < 0

Source: self-made

Asked: Is yz > x?

(1) y > x/z
yz >x if z<>0
NOT SUFFICIENT

(2) z < 0
y & x are unknown
NOT SUFFICIENT

(1) + (2)
(1) y > x/z
yz >x if z<>0
(2) z < 0
Since z<>0
y>x/z
SUFFICIENT

IMO C
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Harley1980
Is yz > x?

(1) y > x/z
(2) z < 0

Source: self-made

(1) Depends on the sign of the z. If z is negative then yz<x but if z is positive then yz>x. INSUFFICIENT.

(2) z<0, No information about y and x. INSUFFICIENT.

Considering both information.
z<0, then y<x. Sufficient.

Ans. C
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