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For option A: Let the numbers be (x-2), (x-1), (x), (x+1), (x+2).

Now, (x-2)+(x-1) + (x) + (x+1) + (x+2) = 5(x). Hence A is true. No need to check other answers since there can only be one correct answer.

So, Ans(A).
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Bunuel
Which of the following MUST yield an integer when divided by 5?

A. The sum of five consecutive positive integers.
B. The square of a prime number.
C. The sum of two odd integers.
D. The product of three consecutive odd numbers.
E. The difference between a multiple of 8 and a multiple of 3.


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A. Plugin numbers: 1+2+3+4+5= 15/5, 12+13+14+15+16=70/5, Hence this holds true for all cases. Lets check the other options as well.
B. 2^2 = 4/5(Not divisible), 5^2(divisible). Not always true.
C. 5+3 not divisible, but 3 + 7 is divisible. Not always true.
D. 1*3*5 is divisible, but 7*9*11 is not. Not always true.
E. 8-3 is divisible, but 16-3 is not.

Hence answer is option A.
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Bunuel
Which of the following MUST yield an integer when divided by 5?

A. The sum of five consecutive positive integers.
B. The square of a prime number.
C. The sum of two odd integers.
D. The product of three consecutive odd numbers.
E. The difference between a multiple of 8 and a multiple of 3.


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800score Official Solution:

(A) Another way to phrase the question is: Which of the following is divisible by 5?

Choice (A) might take some time to figure out. Others are easier.

(B) is wrong — many squares of primes, such as 2², are not divisible by 5.

(C) is also wrong: consider 3 + 9 = 12.

(D) is incorrect; one example is (7)(9)(11), which is not divisible by 5.

(E) can be shown to be wrong as well: For instance, the difference between 16 and 9 is 7.

Choice (A), then, must be correct. If the first of the five consecutive positive integers is x, the full list is:
x + (x +1) + (x + 2) + (x + 3) + (x + 4) = 5x + 10

Since x is an integer, 5x is divisible by 5. 10 is also divisible by 5. Then, 5x + 10 is divisible by 5.
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