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Bunuel
1AB
+AB
___
CDE

In the correctly-worked addition calculation above, A, B, C, D, and E each represent single-digit integers. What is the value of C?

(1) A < 5
(2) B > 4

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Bunuel
1AB
+AB
___
CDE

In the correctly-worked addition calculation above, A, B, C, D, and E each represent single-digit integers. What is the value of C?

(1) A < 5
(2) B > 4

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Statement 1:
A<5
The maximum carry over we can get from addition of two single digit numbers is 1.
Even if we get carry over of 1 from B+B, we cannot get a carry over from A+A since A is less than 5. For example, 4+4+1=9 gives no carry over.
So,there is no carry over from addition of A+A irrespective of the value of B. And c will be 1.
SUFFICIENT

Statement 2:
B>4
Doesn't provide any information about A.
INSUFFICIENT

Answer:- A
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1st statement is enough,
as at max A can have value 4, so 4+4+1(maximum possible value)=9 will not generate any carry,
and hence we can say C will be equal to 1,
hence
IMO A
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It's well understood. Good question.
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There's a 1 in the hundreds digit of the first addition factor, so C can either be:
1, if there's no carry over
2, if there is carry over

Take the first statement:
Because A<5,
The sum A+A can at most be 8
Whether B+B is equal to or greater than 10, meaning there's a carry over into the tens digit, the tens digit of the result would at most be 9, meaning that there can't be a carry over into the hundreds digit in any case: C must be equal to 1
SUFFICIENT

Take the second statement:
Because B>4,
A+A could be greater than or equal to 10: carry over, the hundreds digit would be 2
A+A could be 9: if there's a carry over into the tens digit, depending on the value of B, the hundreds digit would be 2
A+A could be less than 9: whether or not there's a carry over into the tens digit, the hundreds digit would be 1
NOT sufficient

The answer is A
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