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08 Dec 2015, 03:06
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
81% (01:59) correct
19%
(02:26)
wrong
based on 486
sessions
History
Date
Time
Result
Not Attempted Yet
Walking at 60% of his usual speed a man takes 24 minutes more to cover a distance. What is his usual time to cover this distance?
A. 30
B. 36
C. 42
D. 48
E. 54
A. 30
B. 36
C. 42
D. 48
E. 54
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08 Dec 2015, 03:15
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speed is inversly proprtional to time
walking at 60% of speed meand 3/5s takes 5/3t.
It takes 24 minutes extra to cover the distance. then
5/3t=t+24
5t=3t+72
2t=72
t=36.
Option B is correct
walking at 60% of speed meand 3/5s takes 5/3t.
It takes 24 minutes extra to cover the distance. then
5/3t=t+24
5t=3t+72
2t=72
t=36.
Option B is correct
26 Nov 2021, 02:57
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Official Solution:
Walking at 60% of his usual speed a man takes 24 minutes more to cover a distance. What is his usual time to cover this distance?
A. \(30\)
B. \(36\)
C. \(42\)
D. \(48\)
E. \(54\)
Say the usual speed and the usual time are \(s\) and \(t\), respectively. Then the distance is \(d=st\).
The distance can also be expressed as \(d=(0.6s)(t+24)\)
Equate: \(st=(0.6s)(t+24)\);
Reduce by \(s\) and solve to get \(t=36\).
Answer: B
Walking at 60% of his usual speed a man takes 24 minutes more to cover a distance. What is his usual time to cover this distance?
A. \(30\)
B. \(36\)
C. \(42\)
D. \(48\)
E. \(54\)
Say the usual speed and the usual time are \(s\) and \(t\), respectively. Then the distance is \(d=st\).
The distance can also be expressed as \(d=(0.6s)(t+24)\)
Equate: \(st=(0.6s)(t+24)\);
Reduce by \(s\) and solve to get \(t=36\).
Answer: B
