anik1989
CounterSniper
here only 182 is divisible by 14
so it should be A
solving using the data in the question-
as W is divisible by 14
w =14x (where x can be some positive integer)
also
w-3=15P+14 => W=15p+17
subtract 17 from the answer choices 182-17=165 which is divisible by 15 so A
thank you very much. but one more step ahead, i want to know , if i proceed this problem without any option, then what should be my approach?
Hi,
incase you do not have choices or you do not want to substitute values, i would think of following way as a quick method of finding the answer..
W is div by 14..
W-3, when divided by 15 gives you 14 as remainder..
this means if i add 1 to W-3, the remainder will increase to 15 or W-2 is div by 15..
in other words W would leave a remainder of 2, when div by 15..
armed with the info that W leaves a remainder of 0, when div by 14 and 2, when div by 15, we can move to next step...
first we find the number that is div by both and that would be the LCM of 14 and 15..
so 14 * 15 would leave a remainder 0, when div by 14 or 15..
when we take a lower multiple of 14, it would leave a remainder equal to the diff of 15 and 14, which is 1..
so for the remainder to be 2, when divided by 15... the 2nd lower multiple of 14 is required, which is 14*(15-2)=14*13
and 14*13=182.. the answer A