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13 Mar 2016, 10:22
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D
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Difficulty:
65%
(hard)
Question Stats:
63% (02:22) correct
37%
(02:15)
wrong
based on 350
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10 distinct integers are arranged in ascending order. The range of the first 7 is 25 and that of last 7 is 30. What is the maximum range of the 10 numbers?
A. 25
B. 27
C. 30
D. 52
E. 55
A. 25
B. 27
C. 30
D. 52
E. 55
14 Mar 2016, 05:23
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Positions: 1 2 3 4 5 6 7 8 9 10
Given: 1st position = x; 4th position = a; 7th position = y; 10th position = b
y - x = 25
Let x be 0 and y = 25. We are asked to maximize the range and the integers are distinct.
b - a = 30 --> b = 30 + a
In order to increase the range, we have to maximize the value of 'b'.
'b' can be maximized by taking the max value of 'a'.
From the assumed values, maximum value of 'a' can be 22.
Therefore, b = 30 + 22 = 52
Range = 52 - 0 = 52
Answer: D
Given: 1st position = x; 4th position = a; 7th position = y; 10th position = b
y - x = 25
Let x be 0 and y = 25. We are asked to maximize the range and the integers are distinct.
b - a = 30 --> b = 30 + a
In order to increase the range, we have to maximize the value of 'b'.
'b' can be maximized by taking the max value of 'a'.
From the assumed values, maximum value of 'a' can be 22.
Therefore, b = 30 + 22 = 52
Range = 52 - 0 = 52
Answer: D
General Discussion
18 Mar 2016, 03:09
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S7-S1 = 25
S10-S4 = 30
S1 = s7 -25
s10 = s4 + 30
S10 - s1 = s4 - s7 + 55 maximum range when s4 - s7 is minimum since s7 > s4, the min. value can be 3 as these are distinct
= 52 answer
S10-S4 = 30
S1 = s7 -25
s10 = s4 + 30
S10 - s1 = s4 - s7 + 55 maximum range when s4 - s7 is minimum since s7 > s4, the min. value can be 3 as these are distinct
= 52 answer
