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16 Mar 2016, 05:34
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A developer has land that has x feet of lake frontage. The land is to be subdivided into lots, each of which is to have either 80 feet or 100 feet of lake frontage. If 1/9 of the lots are to have 80 feet of frontage each and the remaining 40 lots are to have 100 feet of frontage each, what is the value of x ?
A. 400
B. 3,200
C. 3,700
D. 4,400
E. 4,760
A. 400
B. 3,200
C. 3,700
D. 4,400
E. 4,760
17 Mar 2016, 02:26
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Total number of plots,be T
Plots with 80ft is (1/9)th of total plots.
Plots with 100ft frontage = (8/9) X total number of plots
i.e 8/9 X T = 40 T = 45
Total lake frontage = 40X100 + 5X80 = 4400
Posted from my mobile device
Plots with 80ft is (1/9)th of total plots.
Plots with 100ft frontage = (8/9) X total number of plots
i.e 8/9 X T = 40 T = 45
Total lake frontage = 40X100 + 5X80 = 4400
Posted from my mobile device
12 Jul 2018, 02:50
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A developer has land that has x feet of lake frontage. The land is to be subdivided into lots, each of which is to have either 80 feet or 100 feet of Lake Frontage. If (1/9) of the lots are to have 80 feet of frontage each and the remaining 40 lots are to have 100 feet of frontage each, what is the value of x?
(1/9)ths of the lots are to have 80 feet of frontage each which means remaining lot for 100 feet frontage is [(9-1)/9]X = 8/9
8Y/9 = 40 => Y = 40*9/8 = 5*9 = 45 lot
Remaining lots for 80 Feet are 5 lots.
Total X feet of lake frontage = 80*5 + 40*100 = 400 + 4000 = 4400
Answer D
(1/9)ths of the lots are to have 80 feet of frontage each which means remaining lot for 100 feet frontage is [(9-1)/9]X = 8/9
8Y/9 = 40 => Y = 40*9/8 = 5*9 = 45 lot
Remaining lots for 80 Feet are 5 lots.
Total X feet of lake frontage = 80*5 + 40*100 = 400 + 4000 = 4400
Answer D
