A certain car's price decreased by 2.5% (from the original price) each year from 1996 to 2002, during that time the owner of the car invested in a new carburetor and a new audio system for the car, which increased car's price by $1,500. If the price of the car in 1996 was $22,000, what is the car's price in 2002?
A. $18,400
B. $19,500
C. $20,200
D. $20,400
E. $21,100
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Number of years from 1996 to 2002 = 6
Price of the car in 1996 = $22,000
Price decreased each year by 2.5%
We know that the price decreased 6 times @ 2.5% each year as the number of years from 1996 to 2002 is 6
Therefore, in place of going for lengthy and complicated calculation just multiply 2.5 with 6 -
2.5 * 6 = 15
Now, calculate 15% of $22,000
15/100 * 22,000 = $3300
Price of the car after decreasing the price for continuous 6 years @ 2.5%
= Price of Car in year 1996 (Initial Price) - Price decreased in 6 years
= $22,000 - $3300
= $18700
It is mentioned that the car's price increased by $1,500 with the investment in a new carburetor and a new audio system for the car
therefore, the final price of the car in year 2002 is -
= $18,700 + 1,500
= $20,200
Answer is 'C'