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11 Jul 2016, 12:42
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E
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Difficulty:
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Question Stats:
89% (00:57) correct
11%
(01:21)
wrong
based on 247
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There are 18 balls in a jar. You take out 3 blue balls without putting them back inside, and now the probability of pulling out a blue ball is 1/5. How many blue balls were there in the beginning?
A. 12.
B. 9.
C. 8.
D. 7.
E. 6.
A. 12.
B. 9.
C. 8.
D. 7.
E. 6.
15 Jul 2017, 07:21
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ehsan090
There are 18 balls in a jar. You take out 3 blue balls without putting them back inside, and now the probability of pulling out a blue ball is 1/5. How many blue balls were there in the beginning?
A. 12.
B. 9.
C. 8.
D. 7.
E. 6.
Say there are x blue balls.
If we take out 3 blue balls without putting them back inside, the probability of pulling out a blue ball will be 1/5, so (x - 3)/(18 - 3) = 1/5. Solving gives x = 6.
Answer: E.
General Discussion
09 Jul 2017, 04:44
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There are 18 balls in total and 3 are removed without replacement . So there are total of 18-3=15 balls remaining. the probability of drawing the remaining blue balls is 1/5 and lets says there are n balls remaining out of a total of 15 balls. So n/15=1/5 therefore n=3+ 3 which were removed in the beginning =6
