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24 Jul 2016, 09:12
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
68% (01:34) correct
32%
(01:37)
wrong
based on 459
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In certain year in Country C, x sets of twins and y sets of triplets were born. If there were z total babies born in Country C in this year, and x and y were both greater than 0, which of the following represents the fraction of all babies born who were NOT part of a set of twins or triplets?
A. z - 2x - 3y
B. (2x+3y)/z
C. (x+y)/z
D. 1 - (2x+3y)/z
E. 1 - (x+y)/z
A. z - 2x - 3y
B. (2x+3y)/z
C. (x+y)/z
D. 1 - (2x+3y)/z
E. 1 - (x+y)/z
24 Jul 2016, 09:42
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Bunuel
X set of twins implies 2x babies of twin category.
Y set of triplets means 3y babies of triplet category.
Let K be the babies other than twin or triplet category.
Total babies = z = 2x+3y+k.
or K=Z-(2x+3y)
=> Fraction of babies other than twin or triplet categories = K/Z = Z-(2x+3y)/Z.
= 1- (2x+3y)/Z. Hence answer is D.
19 Apr 2019, 07:59
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the qq might seem tricky at first but if you think about it for a sec turns out to be pretty easy.
set of twins = x ----> number of baby twins = 2x
set of twins = y ----> number of baby triplets = 3y
babies born out of the twins and triplets set = 1-(2x+3y)
proportion of babies born out of the twins and triplets set = 1-(2x+3y)/z
IMO: D
cheers and kudos plz!
set of twins = x ----> number of baby twins = 2x
set of twins = y ----> number of baby triplets = 3y
babies born out of the twins and triplets set = 1-(2x+3y)
proportion of babies born out of the twins and triplets set = 1-(2x+3y)/z
IMO: D
cheers and kudos plz!
