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31 Jan 2017, 10:10
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
72% (00:51) correct
28%
(00:59)
wrong
based on 631
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How many different subcommittees can be formed among the six members of the housing committee?
(1) All subcommittees must have at least two members.
(2) Any combination of members is acceptable except those with 1 member.
(1) All subcommittees must have at least two members.
(2) Any combination of members is acceptable except those with 1 member.
31 Jan 2017, 10:32
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Statements 1 and 2 give the same information, hence the possible answers are D or E.
Let's use complement strategy: P(A)= 1 - P(NOT A).
Wrong possibilities--> subcommitties with only 1 member--> 6 members--> 6 possible subcommitties.
Total possible subcommitties: 6! = 720.
P(A) = 720 - 6 = 714.
Answer D
Let's use complement strategy: P(A)= 1 - P(NOT A).
Wrong possibilities--> subcommitties with only 1 member--> 6 members--> 6 possible subcommitties.
Total possible subcommitties: 6! = 720.
P(A) = 720 - 6 = 714.
Answer D
23 Apr 2017, 05:42
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Total number of ways of forming :
3 committees of 2 members each = 6C2 x 4C2 = 90
2 committees of 3 members each = 6C3 = 20
2 committees of 4 and 2 members = 6C4 = 15
Total number of ways = 125
3 committees of 2 members each = 6C2 x 4C2 = 90
2 committees of 3 members each = 6C3 = 20
2 committees of 4 and 2 members = 6C4 = 15
Total number of ways = 125
