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Bunuel
A car dealership orders 80 automobiles from the factory and wants to sell each for $22,275. 60 of the cars are sold at this price, which represented an 8% profit above the dealership’s cost from the factory. To sell the remaining 20 cars, the dealership has to substantially discount the retail price, and each is sold at a price that represents a 4% loss below the dealership’s cost. What was the dealership’s profit or loss as a percent of the dealership’s initial cost for the 80 automobiles?

A. 5% loss
B. 4% loss
C. 2% profit
D. 4% profit
E. 5% profit


weighted avg. is rather much faster method for above such problems

Let x be avg. profit/loss

then

60/20= (-4-x)/x-8

3x-24= -4-x

4x = 20

x=5

ans E
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Bunuel
A car dealership orders 80 automobiles from the factory and wants to sell each for $22,275. 60 of the cars are sold at this price, which represented an 8% profit above the dealership’s cost from the factory. To sell the remaining 20 cars, the dealership has to substantially discount the retail price, and each is sold at a price that represents a 4% loss below the dealership’s cost. What was the dealership’s profit or loss as a percent of the dealership’s initial cost for the 80 automobiles?

A. 5% loss
B. 4% loss
C. 2% profit
D. 4% profit
E. 5% profit

$22,275 represented 8% profit, so the cost is \(\frac{22,275}{1.08}=20,625\)

Sell remaining 20 cars at price: \(20,625 \times 0.96 = 19,800\)

The total revenue: \(60 \times 22,275 + 20 \times 19,800\)
The total cost: \(80 \times 20,625\)

The profit/loss ratio: \(\frac{(60 \times 22,275 + 20 \times 19,800) - 80 \times 20,625}{80 \times 20,625}\)
\(=\frac{6 \times 22,275 + 2 \times 19,800}{8 \times 20,625} - 1 \\
= \frac{3 \times 22,275 + 19,800}{4 \times 20,625} - 1 \\
= 1.05 - 1 = 0.05 = 5 \%\)

The answer is E.
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Bunuel
A car dealership orders 80 automobiles from the factory and wants to sell each for $22,275. 60 of the cars are sold at this price, which represented an 8% profit above the dealership’s cost from the factory. To sell the remaining 20 cars, the dealership has to substantially discount the retail price, and each is sold at a price that represents a 4% loss below the dealership’s cost. What was the dealership’s profit or loss as a percent of the dealership’s initial cost for the 80 automobiles?

A. 5% loss
B. 4% loss
C. 2% profit
D. 4% profit
E. 5% profit

We are given that 60 cars were sold for $22,275 at a profit of 8%. Thus:

Profit = 0.08(cost)

Revenue - cost = 0.08(cost)

22,275 - c = 0.08c

22,275 = 1.08c

22,275/1.08 = c

20,625 = c

Thus, the dealership’s cost for each car was 20,625 dollars.

We are also given that 20 cars were sold at a loss of 4%. Thus, each of the remaining 20 cars was sold at 96% of the dealership’s cost.

Thus, each of the remaining 20 cars was sold for 0.96(20,625) = $19,800.

In total, the dealership spent 20,625 x 80 = 1,650,000 on the cars and earned:

22,275 x 60 + 19,800 x 20 = 1,336,500 + 396,000 = 1,732,500

Thus, the dealership made a profit on the sale of 80 cars and the profit is:

[(1,732,000 - 1,650,000)/1,650,000] x 100 = (82,000/1,650,000) x 100 = 0.05 x 100 = 5%.

Answer: E
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Can be solved quickly using weighted average concept.

96 (4% loss, 20 cars(weightage) ) <------------------------------------------> 108 (8% profit, 60 cars (weightage))

60:20 = 3 : 1

96 <--------------3------------------->|<--------1-------->108

so the diff between 108 - 96 , must be divided in 3:1 ratio (60:20) according to weightage
so weighted average = \(96 + (12 * 3/4) = 105\) = 5% profit, Answer (E)

Thanks
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The awkward numbers in this problem and the seemingly tedious calculations required to solve it are a hint to look for a faster approach. While you could calculate the total profit on the 60 cars and the total loss on the 20 cars, combine, and divide by the total cost to the dealership, this would take a very, very long time Since the problem is about percentage profit or loss, the values of the cars are not important. The answer will be the same if it is a $10,000 car, a $15,000 car or a $22,275 car. This is really just a good old-fashioned weighted average problem. ¾ of the cars were sold at an 8% profit and ¼ were sold at a 4% loss. This means the ratio of cars with a profit to cars with a loss is 3:1 and this controls the weighting between +8% and -4%. Using the mapping strategy, see that the combined profit would be 5%:

-4% ------------------------------5%-------8%
----------------9%----------------------3%-----
The ratio of 8% profit to 4% loss is the correct 3:1.

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I just did 8*(3/4) + (-4)*(1/4) = 6 - 1 = +5%.
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Le the C.P. of 1 car is 100.

Total C.P.: 80 * 100 = 8,000

Total S.P.: 60 cars with 8% profit and 20 cars with a 4% loss

=> 60 * \(\frac{108}{100}\) * 100 + 20 * \(\frac{96}{100}\) * 100

=> 6480 + 1920

=> 8,400


Overall Profit: S.P. - C.P.

=> 8,400 - 8,000 = 400

Profit percentage: \(\frac{400 }{ 8000}\) * 100 = 5%

Answer E
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the weight of the car sold at profit and loss is 60:20 =>3:1

\(\frac{108(3)+96(1)}{4} = 105\) hence 5% profit
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The best way to solve this ques is using weighted average.

{8*60+(-4)*20}/80 =5

E. 5% Profit
Bunuel
A car dealership orders 80 automobiles from the factory and wants to sell each for $22,275. 60 of the cars are sold at this price, which represented an 8% profit above the dealership’s cost from the factory. To sell the remaining 20 cars, the dealership has to substantially discount the retail price, and each is sold at a price that represents a 4% loss below the dealership’s cost. What was the dealership’s profit or loss as a percent of the dealership’s initial cost for the 80 automobiles?

A. 5% loss
B. 4% loss
C. 2% profit
D. 4% profit
E. 5% profit
­
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Hi Bunuel

Are there more such questions like this where we can practice and solve using weighted averages method?
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DNS96
Hi Bunuel

Are there more such questions like this where we can practice and solve using weighted averages method?

You can use the search box in the PS forum to find similar questions by entering key words like profit, loss, and cost.



Here is a result:

search.php?keywords=profit+lost+cost&terms=all&fid%5B%5D=140&author=&sc=1&sk=re&sd=d&d_s=1&sf=all&sr=posts&sj=one&t=0&submit=Search
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GMAT-Club-Forum-57r2lvy9.png
GMAT-Club-Forum-57r2lvy9.png [ 29.58 KiB | Viewed 1777 times ]
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Understood, thank you Bunuel!

Bunuel
DNS96
Hi Bunuel

Are there more such questions like this where we can practice and solve using weighted averages method?

You can use the search box in the PS forum to find similar questions by entering key words like profit, loss, and cost.



Here is a result:

search.php?keywords=profit+lost+cost&terms=all&fid%5B%5D=140&author=&sc=1&sk=re&sd=d&d_s=1&sf=all&sr=posts&sj=one&t=0&submit=Search
Attachment:
GMAT-Club-Forum-wulr77tl.png
GMAT-Club-Forum-wulr77tl.png [ 29.58 KiB | Viewed 1763 times ]
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Here the absurd number (22,275) given as price is of no use. See below why:

The question asks us to find the overall profit or loss after selling 80 cars, as a percentage of initial cost of 80 cars.

Since we are given a relation in Cost and 22,275 i.e., by telling 8% profit above cost = 22,275. We don't need to put this in the expression to find 60 cars revenue i.e., instead of writing [60 (cars) * 22,275], we can say [60 (cars) * 1.08 (including profit) * Cost Price]

Therefore, the overall expression becomes

[60 (cars) * 1.08 (including profit) * Cost] + [20 (cars) * 0.96 (including loss) * Cost]

divided by

[80 (cars) * Cost]


Cost cancels out in numerator and denominator

Hence: the expression becomes: 60*1.08 + 20*0.96 / 80 = 1.05 => 5 percent profit



Bunuel
A car dealership orders 80 automobiles from the factory and wants to sell each for $22,275. 60 of the cars are sold at this price, which represented an 8% profit above the dealership’s cost from the factory. To sell the remaining 20 cars, the dealership has to substantially discount the retail price, and each is sold at a price that represents a 4% loss below the dealership’s cost. What was the dealership’s profit or loss as a percent of the dealership’s initial cost for the 80 automobiles?

A. 5% loss
B. 4% loss
C. 2% profit
D. 4% profit
E. 5% profit
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