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Bunuel
1, 1, 3, 3, 4, 5, x, y, z

If the list of numbers above has exactly one mode, which of the following could be that mode?

I. 1
II. 4
III. x

A. I only
B. III only
C. I and III only
D. I, II, and III
E. None of the above

Let’s analyze each Roman numeral to determine which could be the mode.

I. 1

If x, y, and z are 1, then 1 could be the mode.

II. 4

If x, y, and z are 4, 4 could be the mode.

III. x

If y = x and z = x, then x could also be the mode.

Answer: D
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Bunuel
1, 1, 3, 3, 4, 5, x, y, z

If the list of numbers above has exactly one mode, which of the following could be that mode?

I. 1
II. 4
III. x

A. I only
B. III only
C. I and III only
D. I, II, and III
E. None of the above

How can x=y=z here? I understand it is not mentioned explicitly that they are different. Is this sufficient to assume they could equal?
I mean if x, y, and z are different then only "1" can be the mode if any one of x,y,z is 1 (or mode=3 if any one of x,y,z is 3)
:roll:
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Bunuel
1, 1, 3, 3, 4, 5, x, y, z

If the list of numbers above has exactly one mode, which of the following could be that mode?

I. 1
II. 4
III. x

A. I only
B. III only
C. I and III only
D. I, II, and III
E. None of the above

How can x=y=z here? I understand it is not mentioned explicitly that they are different. Is this sufficient to assume they could equal?
I mean if x, y, and z are different then only "1" can be the mode if any one of x,y,z is 1 (or mode=3 if any one of x,y,z is 3)
:roll:

Unless it is explicitly stated otherwise, different variables CAN represent the same number.
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Bunuel
1, 1, 3, 3, 4, 5, x, y, z

If the list of numbers above has exactly one mode, which of the following could be that mode?

I. 1
II. 4
III. x

A. I only
B. III only
C. I and III only
D. I, II, and III
E. None of the above

For the answer to be true, shouldn't it be explicitly mentioned here that the given list is not in order? Cz if the list is in order, 1 and 4 can't be the mode. Only 5 and the numbers beyond can be mode.
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