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Answer cannot be determined as we don't know initial positions of trains relative to each other. Answers posted would work if both the trains started from the same point and at the same time. Hence E
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Answer cannot be determined as we don't know initial positions of trains relative to each other. Answers posted would work if both the trains started from the same point and at the same time. Hence E
Thought the same, however answered D..will wait for the formal response.
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Bunuel
Two trains are headed along parallel tracks in the same direction at varying rates of 72 mph and 47 mph. In how many hours will the faster train be 100 miles in front of the slower train?

(A) 2

(B) 2.5

(C) 3.5

(D) 4

(E) Cannot be determined by information provided.

As the realtive speed is 25mph. In an hr the fast train will be 25 miles ahead. So to cover 100 miles the fast train needs 4 hrs.

Ans:D
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Bunuel
Two trains are headed along parallel tracks in the same direction at varying rates of 72 mph and 47 mph. In how many hours will the faster train be 100 miles in front of the slower train?

(A) 2

(B) 2.5

(C) 3.5

(D) 4

(E) Cannot be determined by information provided.

Let t = the time in hours the two trains have traveled when the faster train is 100 miles ahead of the slower train. So, the distances traveled by the faster train and slower train are 72t and 47t, respectively, and we can create the following equation:

72t = 47t + 100

25t = 100

t = 4

Answer: D
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Bunuel
Two trains are headed along parallel tracks in the same direction at varying rates of 72 mph and 47 mph. In how many hours will the faster train be 100 miles in front of the slower train?

(A) 2

(B) 2.5

(C) 3.5

(D) 4

(E) Cannot be determined by information provided.

t=time, r=rate
when the difference between the distances will be 100:
d=tr, we are looking for d1-d2=100 => t*r1-t*r2=100, 72t-47t=100, t=4 => D
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Since the trains are headed in same direction we can simply subtract the speeds and divide the distance by that
i.e 100/(72-47)=4 hours
D should be the correct choice.

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speed of train 1=72 miles/hour
speed of train 2=47 miles/hour
relative speed =72-47 = 25
so time when faster train is ahead by 100 miles = 100/25 = 4hours
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Bunuel
Two trains are headed along parallel tracks in the same direction at varying rates of 72 mph and 47 mph. In how many hours will the faster train be 100 miles in front of the slower train?

(A) 2

(B) 2.5

(C) 3.5

(D) 4

(E) Cannot be determined by information provided.
Initial separation=100 miles
Since the are traveling in the same direction, we have to subtract the relative speed


Time = initial separation/ relative speed
= 100/25
= 4 hours

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Bunuel
Two trains are headed along parallel tracks in the same direction at varying rates of 72 mph and 47 mph. In how many hours will the faster train be 100 miles in front of the slower train?

(A) 2

(B) 2.5

(C) 3.5

(D) 4

(E) Cannot be determined by information provided.

let time = t
72*t=47*t+100
t= 100/25 ; 4 hrs
IMO D
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cbh
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Answer cannot be determined as we don't know initial positions of trains relative to each other. Answers posted would work if both the trains started from the same point and at the same time. Hence E
Thought the same, however answered D..will wait for the formal response.





VERY GOOD POINT!!
VERY GOOD POINT!!
VERY GOOD POINT!!
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