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09 Sep 2017, 01:04
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
90% (01:38) correct
10%
(01:37)
wrong
based on 96
sessions
History
Date
Time
Result
Not Attempted Yet
A lumberjack cuts one-seventh of a log pile in the morning and one-sixth of the remaining logs that afternoon. If he still has 60 more logs to cut, how many logs were there originally?
A) 100
B) 95
C) 84
D) 80
E) 66
Source: 800Score
P.S. - Please do not post just the answers saying - "A" for me or "I'll go with B etc.
A) 100
B) 95
C) 84
D) 80
E) 66
Source: 800Score
P.S. - Please do not post just the answers saying - "A" for me or "I'll go with B etc.
09 Sep 2017, 02:03
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HKD1710
Logs left after morning work \(= 1-\frac{1}{7} = \frac{6}{7}\)
Logs cut in the afternoon \(= \frac{6}{7}*\frac{1}{6} = \frac{1}{7}\)
so logs left after afternoon \(= \frac{6}{7}-\frac{1}{7} = \frac{5}{7}\)
\(\frac{5}{7}\) of total logs \(= 60\)
Hence total logs \(= 84\)
Option C
--------------------------------------------------------
Other methods could be
1.) Assume total logs as \(x\) and then as per the question formulate an equation and solve for \(x\)
2.) Assume total logs to be a convenient multiple of both \(7\) & \(6\) (say \(420\)) and then use equivalence between the arrived number of logs left and original number of logs left
3.) Work backwards through options. Chose a smart number that is multiple of both \(7\) & \(6\) from the options. In this case \(84\) fits the bill perfectly
09 Sep 2017, 08:30
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HKD1710
The number of logs must be divisible by 7.
He cuts \(\frac{1}{7}\) of the logs in the morning.
The original number must be a multiple of 7 in order to subtract 1/7 from it and still have a whole number of logs.
(The remainder will be a multiple of 6, even if the original is smaller than 42. The remainder will also be a multiple of 5. For this question with these answer choices, the latter two facts do not matter.)
Any choice other than C cannot have 1/7 subtracted from it to yield a whole number.
The only choice that is a multiple of 7 is
ANSWER C
