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02 Nov 2017, 23:13
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Difficulty:
15%
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Question Stats:
82% (01:38) correct
18%
(02:05)
wrong
based on 103
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A trapezoid ABCD is formed by adding the isosceles right triangle BCE with base 5 inches to the rectangle ABED, where DE is t inches. What is the area of the trapezoid in square inches?
(A) 5t + 12.5
(B) 5t + 25
(C) 2.5t + 12.5
(D) (t + 5)^2
(E) t^2 + 25
Attachment:
2017-11-03_1010.png [ 6.55 KiB | Viewed 9242 times ]
03 Nov 2017, 00:35
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Since we are given the isosceles right angled triangle, the base = height(which is 5 inches)
We have been given the rectangle to have a base DE = t inches, which makes the area
of the rectangle as 5t inches.
Also, the area of the triangle will be \(\frac{1}{2}*5*5 = 12.5\)
The area of the trapezoid will be 5t + 12.5 square inches(Option A)
