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Bunuel

In the figure above, BC and DE are parallel, and CD and AE are parallel. If AE, AB and CD are 12, 9 and 6 respectively, what is the area of the figure?

(A) 51
(B) 54
(C) 78
(D) 108
(E) cannot be determined


Attachment:
The attachment 2017-11-07_0943.png is no longer available

Hi All,

attached my approach. Any quick approach for this question??
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Extend Line BC straight until it interests Line AE. Call this Intersection Point = G

Since we are told CD is Parallel to AE, our created Line segment GE will also be Parallel to CD

We are also told that BC is Parallel to DE. The Extension Line Segment we created of CG will be Parallel to DE

We thus have Divided the Entire Figure into 2 figures:

(1) a Right Triangle BAG

(2) a Parallelogram CGDE

The height of the parallelogram is given by the Straight Line Distance between the 2 Parallel, Opposite Sides CD and GE ———> 4

Rule: Opposite, Parallel Sides are Equal in a parallelogram.

Since we are Given that CD = 6, we know Opposite Side GE = 6. We can use GE as our Base.

Area of Parallelogram GCDE = (Base) * (height) = 6 * 4 = 24


Area of Right Triangle BAG = (1/2) * (AB) * (AG)


Leg AG = (Length of AE 12) - (Length of Parallelogram Side GE 6)

AG = (12) - (6) = 6

AB is Given as = 9

Area of Right Triangle BAG = (1/2) * (6) * (9) = 27


Area of entire figure = 24 + 27 = 51


(A)
51

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