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10 Jan 2018, 23:32
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
86% (01:41) correct
14%
(02:33)
wrong
based on 49
sessions
History
Date
Time
Result
Not Attempted Yet
The digits of a four-digit positive integer have a sum of 19. If the ten's digit is twice the units digit and the hundreds digit is 8/3 the units digit, what is the number?
A. 863
B. 1842
C. 2863
D. 8263
E. 9820
A. 863
B. 1842
C. 2863
D. 8263
E. 9820
11 Jan 2018, 00:20
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Four digit number = abcd
a+b+c+d = 19
c=2d
b=8/3d
d can have values 3,6,9
since all are single digit , d can only be 3 or else in case 6 and 9 , b will be 16 and 24
when d =3 , b =8
c=6
and from given sum a will b so number would be 2863
a+b+c+d = 19
c=2d
b=8/3d
d can have values 3,6,9
since all are single digit , d can only be 3 or else in case 6 and 9 , b will be 16 and 24
when d =3 , b =8
c=6
and from given sum a will b so number would be 2863
11 Jan 2018, 03:03
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Bunuel
We are given the following attributes of the number
1. 4 digit number
2. Sum of the digits is 19
3. ten's digit is twice one's digit
4. 3 times the hundreds digit is 8 times the units digit
Eliminating wrong answer options:
Option A is not a 4 digit number
Option E does not satisfy Pt 3(ten's digit is not twice one's digit)
Option B and D do not satisfy Pt 4(3 times the hundreds digit is 8 times the units digit)
Only Option C remains and 2863 is the correct answer
