If the remainder when positive integer y is divided by 9 is 3 and the

Question

If the remainder when positive integer y is divided by 9 is 3 and the remainder when y is divided by 6 is also 3, what is the smallest possible value of y?

A. 3
B. 12
C. 18
D. 21
E. 27

NandishSS · Answer

If the remainder when positive integer y is divided by 9 is 3

y= 9k+3 -->(1)

the remainder when y is divided by 6 is also 3

y= 6k+3 -->(2)

From (1) & (2) if k=0 then it is 3

Hence A

Also you can use Ans options, which gives 3 & 21

ITGMAT · Answer

1st condition: n= 9q+3 so n could be 3, 12, 21, 30
2nd condi : n= 6q + 3 so n could be 3,9, 15, 21, 27
so common term = 3 & 21
check next number - 3+18 =21 which also yields remainder 3 on division by 6 & 9. 
hence smallest value is 3. Answer is A.

SidKan · Answer

1st condition: n= 9q+3 so n could be 3, 12, 21, 30
2nd condi : n= 6q + 3 so n could be 3,9, 15, 21, 27
so common term = 3 & 21
check next number - 3+18 =21 which also yields remainder 3 on division by 6 & 9. 
hence smallest value is 3. Answer is A.

GaurSaini · Answer

y = 9k + 3
y = 6M + 3

LCM(9,6) = 18

Hence y = 18N +3

Now putting values of N as 0,1,2,3...we can get various values of y. Smallest value will be when N=0, i.e. 3.

shantanugaware · Answer

I don't see how it could be any of these. Could you please help me through this one? Thanks.

BrushMyQuant · Answer

The remainder when positive integer y is divided by 9 is 3 and the remainder when y is divided by 6 is also 3

As y leaves same remainder (3) when divided by both 9 and 6
=> y = 3 + Multiple of LCM(9,6)
=> y = 3 + 18k (where k is an integer)
=> y = 18k + 3

Smallest possible value of y = 3 when k = 0

So,  Answer will be A 
Hope it helps!

Watch the following video to MASTER Remainders

https://www.youtube.com/watch?v=P0S6j2uTaj4

bumpbot · Answer

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If the remainder when positive integer y is divided by 9 is 3 and the

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